Permission required decorator in Django - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to import the permission decorator from Django.

Django

from django.contrib.auth.decorators import [1]

Drag options to blanks, or click blank then click option'

Apermission_required

Blogin_required

Cuser_passes_test

Drequire_permission

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'login_required' instead of 'permission_required'.

Trying to import from the wrong module.

The permission_required decorator is imported from django.contrib.auth.decorators to check user permissions.

2fill in blank

medium

Complete the code to require the 'polls.change_poll' permission on the view.

Django

@permission_required('[1]')
def edit_poll(request):
    pass

Drag options to blanks, or click blank then click option'

Apolls.change_poll

Bpolls.add_poll

Cpolls.delete_poll

Dpolls.view_poll

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'add' or 'delete' instead of 'change'.

Omitting the app label 'polls'.

The permission string must match the app label and permission codename exactly. Here, 'polls.change_poll' requires change permission on polls.

3fill in blank

hard

Fix the error in the decorator usage to allow raising 403 error if permission is missing.

Django

@permission_required('polls.change_poll', [1]=True)
def edit_poll(request):
    pass

Drag options to blanks, or click blank then click option'

Araise_error

Bthrow_exception

Craise_exception

Derror_raise

Attempts:

3 left

💡 Hint

Common Mistakes

Using incorrect argument names like 'raise_error'.

Not passing the argument at all.

The correct keyword argument is raise_exception=True to raise a 403 error if permission is denied.

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that maps words to their lengths only if length is greater than 3.

Django

{word: [1] for word in words if [2]

Drag options to blanks, or click blank then click option'

Alen(word)

Blen(word) > 3

Cword.startswith('a')

Dword.upper()

Attempts:

3 left

💡 Hint

Common Mistakes

Using the word itself as value instead of length.

Using wrong condition like startswith.

The dictionary comprehension maps each word to its length using len(word). The condition filters words with length greater than 3 using len(word) > 3.

5fill in blank

hard

Fill all three blanks to create a dictionary comprehension that maps uppercase words to their lengths only if length is greater than 3.

Django

{ [1]: [2] for word in words if [3] }

Drag options to blanks, or click blank then click option'

Aword.upper()

Blen(word)

Clen(word) > 3

Dword.lower()

Attempts:

3 left

💡 Hint

Common Mistakes

Using lowercase for keys instead of uppercase.

Using wrong condition or value.

The keys are uppercase words using word.upper(). The values are lengths with len(word). The condition filters words longer than 3 characters.