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Recall & Review
beginner
What is the purpose of the @permission_required decorator in Django?
It restricts access to a view so that only users with a specific permission can use it. If the user lacks the permission, they are redirected or shown an error.
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beginner
How do you specify which permission a Django view requires using @permission_required?
You pass the permission as a string argument in the format 'app_label.permission_codename' to the decorator.
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intermediate
What happens if a user without the required permission tries to access a view decorated with @permission_required?
By default, the user is redirected to the login page. You can change this behavior by setting the raise_exception=True argument to show a 403 Forbidden error instead.
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beginner
Write a simple example of using @permission_required to require the permission polls.can_vote on a view.
from django.contrib.auth.decorators import permission_required
@permission_required('polls.can_vote')
def vote(request):
# view code here
pass
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intermediate
Can @permission_required be used with class-based views in Django?
Not directly. You can use the PermissionRequiredMixin from django.contrib.auth.mixins to enforce permissions on class-based views.
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What argument format does @permission_required expect for the permission?
A'permission_codename'
B'permission_codename.app_label'
C'app_label.permission_codename'
D'app_label'
✗ Incorrect
The permission must be specified as 'app_label.permission_codename', for example 'polls.can_vote'.
What does setting raise_exception=True in @permission_required do?
ARedirects to login page
BRaises a 403 Forbidden error
CGrants permission automatically
DLogs the user out
✗ Incorrect
Setting raise_exception=True causes Django to raise a 403 Forbidden error instead of redirecting.
Which import is needed to use @permission_required?
The decorator is imported from django.contrib.auth.decorators.
If you want to protect a class-based view with permissions, what should you use?
ANo protection needed
B@permission_required decorator
Clogin_required decorator
DPermissionRequiredMixin
✗ Incorrect
PermissionRequiredMixin is designed for class-based views to enforce permissions.
What happens if an anonymous user accesses a view with @permission_required?
AThey are redirected to login page
BThey get access anyway
CThey see a 404 error
DThey get a 500 server error
✗ Incorrect
Anonymous users are redirected to the login page by default.
Explain how the @permission_required decorator works in Django and how you use it in a function-based view.
Think about how you protect a view so only certain users can use it.
You got /5 concepts.
Describe the difference between using @permission_required and PermissionRequiredMixin in Django.
Consider the type of view you want to protect.
You got /5 concepts.
Practice
(1/5)
1. What is the main purpose of the @permission_required decorator in Django?
easy
A. To restrict access to a view based on user permissions
B. To automatically log users in
C. To change the URL of a view
D. To cache the output of a view
Solution
Step 1: Understand the decorator's role
The @permission_required decorator checks if a user has a specific permission before allowing access to a view.
Step 2: Compare options with the decorator's function
Only To restrict access to a view based on user permissions describes restricting access based on permissions, which matches the decorator's purpose.
Final Answer:
To restrict access to a view based on user permissions -> Option A
Quick Check:
Permission check = restrict access [OK]
Hint: Decorator controls access by permissions, not login or caching [OK]
Common Mistakes:
Confusing permission check with login functionality
Thinking it changes URLs
Assuming it caches view output
2. Which of the following is the correct way to use @permission_required to require the permission app.view_item on a Django view function?
easy
A. @permission_required('app.view_item')\ndef my_view(request):\n pass
B. @permission_required(app.view_item)\ndef my_view(request):\n pass
C. @permission_required('app.view_item', login_url='/login')\ndef my_view():\n pass
D. @permission_required('app.view_item', raise_exception=True)\nclass MyView(View):\n pass
Solution
Step 1: Check correct syntax for permission string
The permission must be a string in quotes, like 'app.view_item'. @permission_required('app.view_item')\ndef my_view(request):\n pass uses this correctly.
Step 2: Confirm usage on a function-based view
@permission_required('app.view_item')\ndef my_view(request):\n pass decorates a function with the correct signature (request parameter). @permission_required(app.view_item)\ndef my_view(request):\n pass misses quotes, C misses request parameter, D decorates a class incorrectly.
Final Answer:
@permission_required('app.view_item')\ndef my_view(request):\n pass -> Option A
Quick Check:
Permission string in quotes + function with request = correct [OK]
Hint: Permission must be a quoted string; function needs request param [OK]
Common Mistakes:
Omitting quotes around permission string
Using decorator on class without proper mixin
Missing request parameter in view function
3. Given this view code, what happens when a user without the app.change_item permission accesses /edit-item/?
D. Decorator must be applied to a class, not a function
Solution
Step 1: Check function signature
The view function must accept at least one parameter, usually request. Here, it is missing.
Step 2: Validate decorator usage
The permission string is quoted correctly, and raise_exception=True is valid. The decorator can be used on functions.
Final Answer:
Missing request parameter in the view function -> Option C
Quick Check:
View needs request param, else error [OK]
Hint: View functions always need request parameter [OK]
Common Mistakes:
Forgetting the request argument in view functions
Thinking raise_exception=True is invalid
Believing decorator only works on classes
5. You want to protect a Django view so that only users with app.add_item permission can access it. If they lack permission, you want to show a 403 error instead of redirecting. Which is the correct way to do this?
hard
A. @permission_required('app.add_item', raise_exception=False)\ndef add_item(request):\n return HttpResponse('Item added')
B. @permission_required('app.add_item', login_url='/login/')\ndef add_item(request):\n return HttpResponse('Item added')
C. @permission_required('app.add_item')\ndef add_item(request):\n return HttpResponse('Item added')
D. @permission_required('app.add_item', raise_exception=True)\ndef add_item(request):\n return HttpResponse('Item added')
Solution
Step 1: Understand the effect of raise_exception
Setting raise_exception=True causes Django to return a 403 Forbidden error if the user lacks permission.
Step 2: Check other options for behavior
Options A, B, and C redirect to login or default behavior (no raise_exception=True); only D raises a 403.
Final Answer:
@permission_required('app.add_item', raise_exception=True)\ndef add_item(request):\n return HttpResponse('Item added') -> Option D
Quick Check:
raise_exception=True = 403 error [OK]
Hint: Use raise_exception=True for 403 error on missing permission [OK]