This example shows how to get all users and then only users who are 18 or older. It prints their names to the console.
Django
from django.db import models
class User(models.Model):
name = models.CharField(max_length=100)
age = models.IntegerField()
# Imagine we have these users in the database:# User(name='Alice', age=25)# User(name='Bob', age=17)# User(name='Charlie', age=30)# Get all users
all_users = User.objects.all()
# Get users aged 18 or older
adult_users = User.objects.filter(age__gte=18)
# Print names of all usersprint('All users:')
for user in all_users:
print(user.name)
# Print names of adult usersprint('\nAdult users:')
for user in adult_users:
print(user.name)
OutputSuccess
Important Notes
Use filter() to narrow down results with conditions.
Both methods return QuerySets, which act like lists but get data only when needed.
You can chain filters for more complex queries, like .filter(age__gte=18).filter(name__startswith='A').
Summary
all() gets every record from a table.
filter() gets records that match your conditions.
Use these methods to easily find and work with data in Django.
Practice
(1/5)
1. What does the all() method do in Django's QuerySet?
easy
A. It retrieves all records from the database table.
B. It filters records based on a condition.
C. It deletes all records from the table.
D. It updates all records with new values.
Solution
Step 1: Understand the purpose of all()
The all() method returns every record from the database table without any filtering.
Step 2: Compare with other methods
Unlike filter(), which selects records based on conditions, all() fetches everything.
Final Answer:
It retrieves all records from the database table. -> Option A
Quick Check:
all() = fetch all records [OK]
Hint: Remember: all() means get everything, no conditions [OK]
Common Mistakes:
Confusing all() with filter()
Thinking all() deletes or updates records
Assuming all() needs conditions
2. Which of the following is the correct syntax to get all objects from a Django model named Book?
easy
A. Book.objects.all()
B. Book.objects.filter()
C. Book.all()
D. Book.filter()
Solution
Step 1: Recall Django QuerySet syntax
To get all records, use Model.objects.all(). Here, the model is Book.
Step 2: Check each option
The correct syntax is Book.objects.all(). Using filter() without conditions, calling filter() directly on the model, or omitting .objects like Book.all() are incorrect.
Final Answer:
Book.objects.all() -> Option A
Quick Check:
Correct syntax = Book.objects.all() [OK]
Hint: Use Model.objects.all() to get all records [OK]
Common Mistakes:
Omitting .objects before all()
Using filter() without conditions
Calling all() directly on model
3. Given the following code, what will books contain?
books = Book.objects.filter(author='Alice')
medium
A. All books in the database.
B. Books where the title is 'Alice'.
C. Books where the author is 'Alice'.
D. An error because filter needs multiple conditions.
Solution
Step 1: Understand filter() usage
The filter() method selects records matching the condition inside it. Here, it looks for books with author='Alice'.
Step 2: Analyze the code result
The variable books will be a QuerySet of all books whose author field equals 'Alice'.
Final Answer:
Books where the author is 'Alice'. -> Option C
Quick Check:
filter(author='Alice') = books by Alice [OK]
Hint: filter() returns only matching records [OK]
Common Mistakes:
Thinking filter() returns all records
Confusing author with title field
Assuming filter() needs multiple conditions
4. Identify the error in this Django query:
books = Book.objects.filter('author'='Alice')
medium
A. No error; this query is correct.
B. Using quotes around 'author' inside filter causes a syntax error.
C. Missing parentheses after filter.
D. filter() cannot be used with string conditions.
Solution
Step 1: Check filter() argument syntax
In Django, filter() expects keyword arguments without quotes around the field name. Writing 'author'='Alice' is invalid syntax.
Step 2: Identify correct syntax
The correct way is filter(author='Alice') without quotes around author.
Final Answer:
Using quotes around 'author' inside filter causes a syntax error. -> Option B
Quick Check:
Keyword args in filter() have no quotes [OK]
Hint: Use field_name=value without quotes around field_name [OK]
Common Mistakes:
Putting quotes around field names in filter()
Confusing filter() syntax with dictionary syntax
Assuming filter() accepts string expressions
5. You want to get all books published after 2010 by author 'Bob'. Which Django query is correct?
hard
A. Book.objects.filter(author='Bob').all(published_year__gt=2010)
B. Book.objects.all().filter(author='Bob', published_year>2010)
C. Book.objects.filter(author='Bob', published_year>2010)
D. Book.objects.filter(author='Bob').filter(published_year__gt=2010)
Book.objects.filter(author='Bob').filter(published_year__gt=2010) uses published_year__gt=2010 which means 'greater than 2010', the correct Django syntax. Book.objects.all().filter(author='Bob', published_year>2010) uses invalid syntax with > inside filter. Book.objects.filter(author='Bob', published_year>2010) also uses invalid > operator. Book.objects.filter(author='Bob').all(published_year__gt=2010) misuses all() after filter.
Final Answer:
Book.objects.filter(author='Bob').filter(published_year__gt=2010) -> Option D
Quick Check:
Chain filters and use __gt for greater than [OK]
Hint: Chain filters and use __gt for greater than [OK]
Common Mistakes:
Using > inside filter() instead of __gt
Misusing all() after filter()
Trying to pass multiple conditions incorrectly
Recommended
Ready to prove it?
Pass the test and this pattern moves unknownstrongwhile earning +1 Grip toward your certificate.