Sliding window technique in Data Structures Theory - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to initialize the sliding window start index.

Data Structures Theory

start = [1]

Drag options to blanks, or click blank then click option'

ANone

B-1

C0

D1

Attempts:

3 left

💡 Hint

Common Mistakes

Starting the window at 1 instead of 0.

Using None or negative values as start index.

The sliding window usually starts at index 0 to cover the beginning of the data.

2fill in blank

medium

Complete the code to move the sliding window end index forward by one.

Data Structures Theory

end = [1] + 1

Drag options to blanks, or click blank then click option'

Astart

Bend

Cwindow_size

Dlength

Attempts:

3 left

💡 Hint

Common Mistakes

Adding 1 to start instead of end.

Using window_size or length incorrectly.

To slide the window forward, the end index is increased by one from its current position.

3fill in blank

hard

Fix the error in the code to shrink the sliding window from the left.

Data Structures Theory

start = [1] + 1

Drag options to blanks, or click blank then click option'

Astart

Bend

Cwindow_size

Dlength

Attempts:

3 left

💡 Hint

Common Mistakes

Increasing end instead of start.

Using window_size or length incorrectly.

To shrink the window from the left, increase the start index by one.

4fill in blank

hard

Fill both blanks to create a sliding window dictionary comprehension that stores word lengths for words longer than 3 characters.

Data Structures Theory

{word: [1] for word in words if [2] > 3}

Drag options to blanks, or click blank then click option'

Alen(word)

Cword

Attempts:

3 left

💡 Hint

Common Mistakes

Using word instead of len(word) for length.

Filtering by word instead of its length.

The dictionary comprehension maps each word to its length, filtering words longer than 3 characters using len(word) > 3.

5fill in blank

hard

Fill all three blanks to create a sliding window dictionary comprehension that stores uppercase words and their lengths if length is greater than 4.

Data Structures Theory

{ [1]: [2] for word in words if [3] > 4 }

Drag options to blanks, or click blank then click option'

Aword.upper()

Blen(word)

Dword

Attempts:

3 left

💡 Hint

Common Mistakes

Using word instead of word.upper() as key.

Filtering by word instead of length.

Mixing up key and value positions.

The comprehension uses the uppercase word as key, its length as value, and filters words longer than 4 characters.

Practice

1. What is the main purpose of the sliding window technique in data processing?

easy

A. To efficiently process continuous segments of data without repeated work

B. To sort data in ascending order

C. To store data permanently in memory

D. To randomly access elements in a list

Solution

1. Step 1: Understand the sliding window concept

   The sliding window technique moves a fixed-size window over data to process parts efficiently.

2. Step 2: Identify the main goal

   It avoids repeated calculations by updating results as the window moves, improving efficiency.

3. Final Answer:

   To efficiently process continuous segments of data without repeated work -> Option A

4. Quick Check:

   Sliding window = efficient continuous data processing [OK]

Hint: Think of a moving window checking parts step-by-step [OK]

Common Mistakes:

• Confusing sliding window with sorting algorithms
• Thinking it stores data permanently
• Assuming it accesses data randomly

2. Which of the following is the correct way to initialize a sliding window of size 3 over a list arr in Python?

easy

A. window = arr{0:3}

B. window = arr(0,3)

C. window = arr[0:3]

D. window = arr[3]

Solution

1. Step 1: Recall Python slicing syntax

   Python uses square brackets and colon to slice lists: arr[start:end] extracts elements from start up to but not including end.

2. Step 2: Apply slicing for window size 3

   To get first 3 elements, use arr[0:3]. Other options use incorrect syntax.

3. Final Answer:

   window = arr[0:3] -> Option C

4. Quick Check:

   Python slice for first 3 elements = arr[0:3] [OK]

Hint: Remember Python slices use square brackets and colon [OK]

Common Mistakes:

• Using parentheses instead of brackets for slicing
• Using curly braces which are invalid for lists
• Accessing a single element instead of a slice

3. Consider the Python code below using sliding window to find the maximum sum of any 3 consecutive numbers in arr:

arr = [2, 1, 5, 1, 3, 2]
window_sum = sum(arr[0:3])
max_sum = window_sum
for i in range(3, len(arr)):
    window_sum += arr[i] - arr[i-3]
    if window_sum > max_sum:
        max_sum = window_sum
print(max_sum)

What is the output?

medium

A. 7

B. 8

C. 6

D. 9

Solution

1. Step 1: Calculate initial window sum

   Sum of first 3 elements: 2 + 1 + 5 = 8. Set max_sum = 8.

2. Step 2: Slide window and update sums

   i=3: window_sum = 8 + arr[3] - arr[0] = 8 + 1 - 2 = 7 (max_sum=8)
   i=4: window_sum = 7 + arr[4] - arr[1] = 7 + 3 - 1 = 9 (max_sum=9)
   i=5: window_sum = 9 + arr[5] - arr[2] = 9 + 2 - 5 = 6 (max_sum=9)

3. Final Answer:

   9 -> Option D

4. Quick Check:

   Max sum of 3 consecutive = 9 [OK]

Hint: Add new element, subtract old element to update sum [OK]

Common Mistakes:

• Recalculating sum of window each time instead of updating
• Mixing up indices when subtracting old element
• Not updating max_sum correctly

4. The following code attempts to find the minimum sum of any 2 consecutive numbers in arr using sliding window:

arr = [4, 3, 7, 1, 2]
window_sum = arr[0] + arr[1]
min_sum = window_sum
for i in range(2, len(arr)):
    window_sum = window_sum + arr[i] - arr[i-1]
    if window_sum < min_sum:
        min_sum = window_sum
print(min_sum)

What is the error in this code?

medium

A. The window size is incorrectly handled in subtraction index

B. The loop range should start from 1, not 2

C. The initial window sum is calculated incorrectly

D. The comparison operator in if statement is wrong

Solution

1. Step 1: Analyze window size and indices

   The window size is 2. When sliding to include arr[i], subtract the leaving element arr[i-2].

2. Step 2: Identify the error

   Code subtracts arr[i-1], but should subtract arr[i-2]. arr[i-1] remains in the window.

3. Step 3: Verify with trace

   i=2: should be 7 + 7 - 4 = 10, but code 7 + 7 - 3 = 11 (wrong).

4. Final Answer:

   The window size is incorrectly handled in subtraction index -> Option A

5. Quick Check:

   For size k=2, subtract arr[i-k] [OK]

Hint: Check subtraction index matches window size [OK]

Common Mistakes:

• Using wrong index for element leaving the window
• Starting loop at wrong index
• Incorrect initial sum calculation

5. You want to find the longest substring of a string s that contains at most 2 distinct characters using the sliding window technique. Which approach correctly applies the sliding window here?

hard

A. Fix window size to 2 and slide over the string

B. Expand the window by moving right pointer, shrink from left when distinct chars exceed 2

C. Count total distinct characters in the string once and return that count

D. Use nested loops to check all substrings of length 2

Solution

1. Step 1: Understand problem requirements

   We want the longest substring with at most 2 distinct characters, so window size is variable.

2. Step 2: Apply sliding window logic

   Expand window by moving right pointer. If distinct chars exceed 2, shrink window from left until condition holds.

3. Step 3: Evaluate options

   Expand the window by moving right pointer, shrink from left when distinct chars exceed 2 matches this approach. Fix window size to 2 and slide over the string fixes window size incorrectly. Options C and D do not use sliding window properly.

4. Final Answer:

   Expand the window by moving right pointer, shrink from left when distinct chars exceed 2 -> Option B

5. Quick Check:

   Variable window size with condition check = Expand the window by moving right pointer, shrink from left when distinct chars exceed 2 [OK]

Hint: Adjust window size dynamically based on distinct chars count [OK]

Common Mistakes:

• Fixing window size instead of adjusting dynamically
• Not shrinking window when condition breaks
• Using brute force nested loops instead of sliding window