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Sliding window technique in Data Structures Theory - Practice Problems & Coding Challenges

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🧠 Conceptual
intermediate
2:00remaining
Understanding the Sliding Window Concept

What is the primary advantage of using the sliding window technique in algorithms?

AIt reduces the time complexity by avoiding repeated calculations over overlapping parts of data.
BIt increases memory usage to store all possible subarrays for faster access.
CIt sorts the data first to make searching faster.
DIt uses recursion to break down the problem into smaller parts.
Attempts:
2 left
πŸ’‘ Hint

Think about how the technique handles overlapping sections of data.

πŸš€ Application
intermediate
2:00remaining
Applying Sliding Window to Find Maximum Sum

Given an array of integers, which approach correctly uses the sliding window technique to find the maximum sum of any contiguous subarray of size 3?

Data Structures Theory
arr = [2, 1, 5, 1, 3, 2]
window_size = 3
max_sum = 0
current_sum = 0

# Which option correctly implements the sliding window?
A
max_sum = max(arr)
print(max_sum)
B
max_sum = 0
for i in range(len(arr) - window_size + 1):
    current_sum = sum(arr[i:i+window_size])
    if current_sum > max_sum:
        max_sum = current_sum
print(max_sum)
C
current_sum = sum(arr[:window_size])
max_sum = current_sum
for i in range(window_size, len(arr)):
    current_sum += arr[i] - arr[i - window_size]
    max_sum = max(max_sum, current_sum)
print(max_sum)
D
current_sum = 0
for i in range(len(arr)):
    current_sum += arr[i]
    max_sum = max(max_sum, current_sum)
print(max_sum)
Attempts:
2 left
πŸ’‘ Hint

Look for the option that updates the sum by adding the new element and removing the old one.

πŸ” Analysis
advanced
2:00remaining
Analyzing Time Complexity of Sliding Window

What is the time complexity of a sliding window algorithm that processes an array of length n with a fixed window size k?

AO(n * k) because each window requires summing k elements.
BO(n) because each element is added and removed at most once from the window.
CO(k) because the window size limits the operations.
DO(n log k) because sorting is involved in each window.
Attempts:
2 left
πŸ’‘ Hint

Consider how many times each element is processed during the sliding.

❓ Comparison
advanced
2:00remaining
Comparing Sliding Window with Nested Loops

Which statement correctly compares the sliding window technique with a naive nested loop approach for finding the maximum sum of subarrays of fixed size?

ASliding window is faster because it avoids recalculating sums for overlapping subarrays, while nested loops recalculate sums fully each time.
BNested loops are faster because they use direct summation without extra variables.
CBoth have the same time complexity and performance in practice.
DSliding window uses more memory, making it slower than nested loops.
Attempts:
2 left
πŸ’‘ Hint

Think about how many times sums are recalculated in each method.

❓ Reasoning
expert
2:00remaining
Reasoning About Variable Window Size

In a sliding window algorithm where the window size can change dynamically based on conditions, what is a key challenge compared to a fixed-size window?

AUsing recursion to adjust the window size automatically.
BSorting the window elements each time the size changes to maintain order.
CPrecomputing all possible window sizes before processing the data.
DManaging the window boundaries carefully to ensure all elements are included or excluded correctly as the size changes.
Attempts:
2 left
πŸ’‘ Hint

Think about what changes when the window size is not fixed.

Practice

(1/5)
1. What is the main purpose of the sliding window technique in data processing?
easy
A. To efficiently process continuous segments of data without repeated work
B. To sort data in ascending order
C. To store data permanently in memory
D. To randomly access elements in a list

Solution

  1. Step 1: Understand the sliding window concept

    The sliding window technique moves a fixed-size window over data to process parts efficiently.
  2. Step 2: Identify the main goal

    It avoids repeated calculations by updating results as the window moves, improving efficiency.
  3. Final Answer:

    To efficiently process continuous segments of data without repeated work -> Option A
  4. Quick Check:

    Sliding window = efficient continuous data processing [OK]
Hint: Think of a moving window checking parts step-by-step [OK]
Common Mistakes:
  • Confusing sliding window with sorting algorithms
  • Thinking it stores data permanently
  • Assuming it accesses data randomly
2. Which of the following is the correct way to initialize a sliding window of size 3 over a list arr in Python?
easy
A. window = arr{0:3}
B. window = arr(0,3)
C. window = arr[0:3]
D. window = arr[3]

Solution

  1. Step 1: Recall Python slicing syntax

    Python uses square brackets and colon to slice lists: arr[start:end] extracts elements from start up to but not including end.
  2. Step 2: Apply slicing for window size 3

    To get first 3 elements, use arr[0:3]. Other options use incorrect syntax.
  3. Final Answer:

    window = arr[0:3] -> Option C
  4. Quick Check:

    Python slice for first 3 elements = arr[0:3] [OK]
Hint: Remember Python slices use square brackets and colon [OK]
Common Mistakes:
  • Using parentheses instead of brackets for slicing
  • Using curly braces which are invalid for lists
  • Accessing a single element instead of a slice
3. Consider the Python code below using sliding window to find the maximum sum of any 3 consecutive numbers in arr:
arr = [2, 1, 5, 1, 3, 2]
window_sum = sum(arr[0:3])
max_sum = window_sum
for i in range(3, len(arr)):
    window_sum += arr[i] - arr[i-3]
    if window_sum > max_sum:
        max_sum = window_sum
print(max_sum)
What is the output?
medium
A. 7
B. 8
C. 6
D. 9

Solution

  1. Step 1: Calculate initial window sum

    Sum of first 3 elements: 2 + 1 + 5 = 8. Set max_sum = 8.
  2. Step 2: Slide window and update sums

    i=3: window_sum = 8 + arr[3] - arr[0] = 8 + 1 - 2 = 7 (max_sum=8)
    i=4: window_sum = 7 + arr[4] - arr[1] = 7 + 3 - 1 = 9 (max_sum=9)
    i=5: window_sum = 9 + arr[5] - arr[2] = 9 + 2 - 5 = 6 (max_sum=9)
  3. Final Answer:

    9 -> Option D
  4. Quick Check:

    Max sum of 3 consecutive = 9 [OK]
Hint: Add new element, subtract old element to update sum [OK]
Common Mistakes:
  • Recalculating sum of window each time instead of updating
  • Mixing up indices when subtracting old element
  • Not updating max_sum correctly
4. The following code attempts to find the minimum sum of any 2 consecutive numbers in arr using sliding window:
arr = [4, 3, 7, 1, 2]
window_sum = arr[0] + arr[1]
min_sum = window_sum
for i in range(2, len(arr)):
    window_sum = window_sum + arr[i] - arr[i-1]
    if window_sum < min_sum:
        min_sum = window_sum
print(min_sum)
What is the error in this code?
medium
A. The window size is incorrectly handled in subtraction index
B. The loop range should start from 1, not 2
C. The initial window sum is calculated incorrectly
D. The comparison operator in if statement is wrong

Solution

  1. Step 1: Analyze window size and indices

    The window size is 2. When sliding to include arr[i], subtract the leaving element arr[i-2].
  2. Step 2: Identify the error

    Code subtracts arr[i-1], but should subtract arr[i-2]. arr[i-1] remains in the window.
  3. Step 3: Verify with trace

    i=2: should be 7 + 7 - 4 = 10, but code 7 + 7 - 3 = 11 (wrong).
  4. Final Answer:

    The window size is incorrectly handled in subtraction index -> Option A
  5. Quick Check:

    For size k=2, subtract arr[i-k] [OK]
Hint: Check subtraction index matches window size [OK]
Common Mistakes:
  • Using wrong index for element leaving the window
  • Starting loop at wrong index
  • Incorrect initial sum calculation
5. You want to find the longest substring of a string s that contains at most 2 distinct characters using the sliding window technique. Which approach correctly applies the sliding window here?
hard
A. Fix window size to 2 and slide over the string
B. Expand the window by moving right pointer, shrink from left when distinct chars exceed 2
C. Count total distinct characters in the string once and return that count
D. Use nested loops to check all substrings of length 2

Solution

  1. Step 1: Understand problem requirements

    We want the longest substring with at most 2 distinct characters, so window size is variable.
  2. Step 2: Apply sliding window logic

    Expand window by moving right pointer. If distinct chars exceed 2, shrink window from left until condition holds.
  3. Step 3: Evaluate options

    Expand the window by moving right pointer, shrink from left when distinct chars exceed 2 matches this approach. Fix window size to 2 and slide over the string fixes window size incorrectly. Options C and D do not use sliding window properly.
  4. Final Answer:

    Expand the window by moving right pointer, shrink from left when distinct chars exceed 2 -> Option B
  5. Quick Check:

    Variable window size with condition check = Expand the window by moving right pointer, shrink from left when distinct chars exceed 2 [OK]
Hint: Adjust window size dynamically based on distinct chars count [OK]
Common Mistakes:
  • Fixing window size instead of adjusting dynamically
  • Not shrinking window when condition breaks
  • Using brute force nested loops instead of sliding window
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