Multiple catch blocks in C++ - Mini Project: Build & Apply

Handling Multiple Exceptions with Multiple Catch Blocks in C++

📖 Scenario: Imagine you are writing a simple program that divides two numbers. Sometimes, the user might enter zero as the divisor, which causes an error. Other times, the user might enter a non-number, causing a different error. You want to catch these errors separately and show clear messages.

🎯 Goal: You will create a program that uses try and catch blocks to handle different types of errors separately. This will help the program respond correctly to different problems.

📋 What You'll Learn

Create two integer variables numerator and denominator with values 10 and 0 respectively.

Create a try block where you check if denominator is zero and throw an int exception with value 0 if true.

Add a catch block to catch the int exception and print "Error: Division by zero!".

Add another catch block to catch any other exceptions of type const char* and print "Error: Invalid input!".

💡 Why This Matters

🌍 Real World

Handling errors properly is important in real-world programs to avoid crashes and to give users clear feedback when something goes wrong.

💼 Career

Knowing how to use multiple catch blocks is a key skill for software developers to write safe and reliable C++ applications.

1

Create the initial variables

Create two integer variables called numerator and denominator with values 10 and 0 respectively.

C++

// Your code here

Need a hint?

Use int numerator = 10; and int denominator = 0; to create the variables.

2

Add the try block with exception throwing

Add a try block. Inside it, check if denominator is zero. If yes, throw an int exception with value 0. Otherwise, calculate numerator / denominator and store it in an integer variable called result.

C++

int numerator = 10;
int denominator = 0;

// Add try block and throw exception if denominator is zero
// Your code here

Need a hint?

Use try { ... } and inside it use if (denominator == 0) throw 0;.

3

Add multiple catch blocks

Add two catch blocks after the try block. The first catch block should catch an int exception and print "Error: Division by zero!". The second catch block should catch a const char* exception and print "Error: Invalid input!".

C++

int numerator = 10;
int denominator = 0;

try {
    if (denominator == 0) {
        throw 0;
    }
    int result = numerator / denominator;
}
// Add two catch blocks here
// Your code here

Need a hint?

Use catch (int) { ... } and catch (const char*) { ... } blocks with std::cout to print messages.

4

Print the final output

Add a main function around your code and include #include <iostream>. Run the program to see the output. The program should print Error: Division by zero!.

C++

#include 

// Wrap the code in main function and run
// Your code here

Need a hint?

Make sure to include #include <iostream> and wrap your code inside int main() { ... }. Use std::cout to print the messages.