If–else statement in C++ - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to check if a number is positive.

C++

int num = 5;
if (num [1] 0) {
    std::cout << "Positive" << std::endl;
}

Drag options to blanks, or click blank then click option'

A>

B==

C<

D!=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '==' instead of '>' to check positivity.

Using '<' which checks for negative numbers.

The condition num > 0 checks if the number is positive.

2fill in blank

medium

Complete the code to print "Even" if the number is even.

C++

int num = 4;
if (num % 2 [1] 0) {
    std::cout << "Even" << std::endl;
}

Drag options to blanks, or click blank then click option'

A<

B!=

C>

D==

Attempts:

3 left

💡 Hint

Common Mistakes

Using '!=' which checks for odd numbers.

Using '>' or '<' which are not suitable here.

The condition num % 2 == 0 checks if the number is even.

3fill in blank

hard

Fix the error in the if–else statement to print "Positive" or "Non-positive".

C++

int num = -3;
if (num [1] 0) {
    std::cout << "Positive" << std::endl;
} else {
    std::cout << "Non-positive" << std::endl;
}

Drag options to blanks, or click blank then click option'

A==

B<=

C>

D!=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<=' which reverses the logic.

Using '==' which only checks for zero.

The condition num > 0 correctly checks for positive numbers.

4fill in blank

hard

Fill both blanks to print "Adult" if age is 18 or more, otherwise "Minor".

C++

int age = 20;
if (age [1] 18) {
    std::cout << "Adult" << std::endl;
} else {
    std::cout << "[2]" << std::endl;
}

Drag options to blanks, or click blank then click option'

A>=

B<

CMinor

DAdult

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' instead of '>=' for the condition.

Printing "Adult" in the else block.

The condition age >= 18 checks if the person is an adult. Otherwise, print "Minor".

5fill in blank

hard

Fill all three blanks to print "Positive", "Negative", or "Zero" based on the value of num.

C++

int num = 0;
if (num [1] 0) {
    std::cout << "Positive" << std::endl;
} else if (num [2] 0) {
    std::cout << "Negative" << std::endl;
} else {
    std::cout << "[3]" << std::endl;
}

Drag options to blanks, or click blank then click option'

A>

B<

CZero

D!=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '!=' which does not distinguish zero.

Mixing up the comparison operators.

The first condition checks if num > 0 (positive), the second if num < 0 (negative), else print "Zero".