For loop in C++

Introduction

A for loop helps you repeat a set of instructions many times without writing them again and again.

When you want to count from 1 to 10 and do something each time.

When you need to process each item in a list one by one.

When you want to repeat a task a fixed number of times, like printing a message 5 times.

When you want to sum numbers from 1 to 100 easily.

When you want to run a block of code with a changing number each time.

Syntax

C++

for (initialization; condition; update) {
    // code to repeat
}

initialization runs once at the start.

condition is checked before each loop; if false, loop stops.

update runs after each loop to change the loop variable.

Examples

This loop runs 5 times, with i from 0 to 4.

C++

for (int i = 0; i < 5; i++) {
    // repeat 5 times
}

This loop counts down from 10 to 1.

C++

for (int count = 10; count > 0; count--) {
    // count down from 10 to 1
}

This loop increases i by 2 each time, skipping even numbers.

C++

for (int i = 1; i <= 10; i += 2) {
    // i goes 1, 3, 5, 7, 9
}

Sample Program

This program prints "Hello" followed by numbers 1 to 5, each on a new line.

C++

#include <iostream>

int main() {
    for (int i = 1; i <= 5; i++) {
        std::cout << "Hello " << i << "\n";
    }
    return 0;
}

Important Notes

Make sure the loop condition eventually becomes false, or the loop will run forever.

You can use any variable name for the loop counter, not just i.

The update step can add, subtract, or do other changes to the loop variable.

Summary

For loops repeat code a set number of times.

They have three parts: start, condition, and update.

Use for loops when you know how many times to repeat something.

Practice

1.

What does a for loop in C++ do?

easy

A. Defines a new function

B. Runs code only once

C. Stops the program immediately

D. Repeats a block of code a fixed number of times

Solution

1. Step 1: Understand the purpose of a for loop

   A for loop is designed to repeat code multiple times based on a condition.

2. Step 2: Identify the correct description

   Among the options, only repeating code a fixed number of times matches the for loop's behavior.

3. Final Answer:

   Repeats a block of code a fixed number of times -> Option D

4. Quick Check:

   For loop = repeat fixed times [OK]

Hint: For loops repeat code a set number of times [OK]

Common Mistakes:

• Thinking for loops run only once
• Confusing for loops with if statements
• Believing for loops stop the program

2.

Which of the following is the correct syntax for a for loop in C++?

for (___; i < 5; i++) {
    // code
}

easy

A. int i = 0

B. i = 0

C. int i

D. int i == 0

Solution

1. Step 1: Check initialization syntax in for loop

   The initialization part must declare and initialize the loop variable, e.g., int i = 0.

2. Step 2: Compare options for correctness

   Only int i = 0 correctly declares and initializes the variable.

3. Final Answer:

   int i = 0 -> Option A

4. Quick Check:

   Initialization needs declaration and assignment [OK]

Hint: Initialization needs declaration and assignment [OK]

Common Mistakes:

• Using 'int i' without initialization
• Using 'int i == 0' which is a comparison
• Omitting the type declaration

3.

What is the output of this code?

for (int i = 1; i <= 3; i++) {
    std::cout << i * 2 << " ";
}

medium

A. 1 2 3

B. 2 4 6

C. 0 2 4

D. 2 3 4

Solution

1. Step 1: Identify loop iterations

   The loop runs with i = 1, 2, 3 because condition is i <= 3.

2. Step 2: Calculate output for each iteration

   Outputs are i*2: 2, 4, 6 printed with spaces.

3. Final Answer:

   2 4 6 -> Option B

4. Quick Check:

   Multiply i by 2 each loop [OK]

Hint: Multiply loop variable by 2 each iteration [OK]

Common Mistakes:

• Confusing loop range (off by one)
• Printing i instead of i*2
• Missing spaces in output

4.

Find the error in this for loop:

for (int i = 0; i > 5; i++) {
    std::cout << i << " ";
}

medium

A. Variable i is not declared

B. Missing semicolon after i++

C. The condition 'i > 5' is incorrect, loop never runs

D. The loop will run infinitely

Solution

1. Step 1: Analyze the loop condition

   The condition is i > 5 but i starts at 0, so it is false immediately.

2. Step 2: Understand loop execution

   Since condition is false at start, loop body never executes.

3. Final Answer:

   The condition 'i > 5' is incorrect, loop never runs -> Option C

4. Quick Check:

   Condition false at start means no loop runs [OK]

Hint: Check if loop condition is true initially [OK]

Common Mistakes:

• Assuming loop runs despite false condition
• Thinking missing semicolon causes error here
• Confusing variable declaration errors

5.

How can you use a for loop to print all even numbers from 2 to 10 inclusive?

Choose the correct code snippet:

hard

A. for (int i = 2; i <= 10; i += 2) { std::cout << i << ' '; }

B. for (int i = 1; i < 10; i++) { if (i % 2 == 0) std::cout << i << ' '; }

C. for (int i = 2; i < 10; i++) { std::cout << i * 2 << ' '; }

D. for (int i = 0; i <= 10; i += 3) { std::cout << i << ' '; }

Solution

1. Step 1: Understand the goal

   We want to print even numbers 2,4,6,8,10 inclusive.

2. Step 2: Check each option

   for (int i = 2; i <= 10; i += 2) { std::cout << i << ' '; } increments by 2 starting at 2, printing 2,4,6,8,10 correctly.
   for (int i = 1; i < 10; i++) { if (i % 2 == 0) std::cout << i << ' '; } prints 2,4,6,8 but misses 10.
   for (int i = 2; i < 10; i++) { std::cout << i * 2 << ' '; } prints 4,6,8,10,12,14,16,18 (wrong range).
   for (int i = 0; i <= 10; i += 3) { std::cout << i << ' '; } increments by 3, not even numbers.

3. Final Answer:

   for (int i = 2; i <= 10; i += 2) { std::cout << i << ' '; } -> Option A

4. Quick Check:

   Increment by 2 from 2 to 10 [OK]

Hint: Increment loop variable by 2 starting at 2 [OK]

Common Mistakes:

• Using wrong increment step
• Forgetting to include 10
• Using condition inside loop unnecessarily