Continue statement in C++ - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to skip printing the number 3 in the loop.

C++

#include <iostream>

int main() {
    for (int i = 1; i <= 5; i++) {
        if (i == 3) {
            [1];
        }
        std::cout << i << " ";
    }
    return 0;
}

Drag options to blanks, or click blank then click option'

Acontinue

Bbreak

Creturn

Dexit

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'break' instead of 'continue' which stops the loop completely.

Using 'return' which exits the whole function.

Using 'exit' which ends the program.

The 'continue' statement skips the current iteration and moves to the next one, so number 3 is not printed.

2fill in blank

medium

Complete the code to skip all even numbers in the loop.

C++

#include <iostream>

int main() {
    for (int i = 1; i <= 6; i++) {
        if (i % 2 == 0) {
            [1];
        }
        std::cout << i << " ";
    }
    return 0;
}

Drag options to blanks, or click blank then click option'

Aexit

Bcontinue

Creturn

Dbreak

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'break' which stops the loop entirely.

Using 'return' which exits the function.

Using 'exit' which ends the program.

The 'continue' statement skips printing even numbers by moving to the next iteration.

3fill in blank

hard

Fix the error in the code to correctly skip printing negative numbers.

C++

#include <iostream>

int main() {
    int numbers[] = {2, -1, 3, -4, 5};
    for (int i = 0; i < 5; i++) {
        if (numbers[i] < 0) {
            [1];
        }
        std::cout << numbers[i] << " ";
    }
    return 0;
}

Drag options to blanks, or click blank then click option'

Aexit

Bbreak

Creturn

Dcontinue

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'break' which stops the loop completely.

Using 'return' which exits the function.

Using 'exit' which ends the program.

Using 'continue' skips printing negative numbers and continues the loop.

4fill in blank

hard

Fill both blanks to skip printing multiples of 3 and continue the loop.

C++

#include <iostream>

int main() {
    for (int i = 1; i <= 10; i++) {
        if (i [1] 3 [2] 0) {
            continue;
        }
        std::cout << i << " ";
    }
    return 0;
}

Drag options to blanks, or click blank then click option'

A%

B==

C!=

D/

Attempts:

3 left

💡 Hint

Common Mistakes

Using '/' instead of '%' for modulus.

Using '!=' instead of '==' in the condition.

Using 'break' instead of 'continue'.

The condition 'i % 3 == 0' checks for multiples of 3, and 'continue' skips printing them.

5fill in blank

hard

Fill all three blanks to skip printing numbers less than 5 and continue the loop.

C++

#include <iostream>

int main() {
    int arr[] = {2, 5, 7, 3, 8};
    for (int [1] = 0; [2]; [3]++) {
        if (arr[i] < 5) {
            continue;
        }
        std::cout << arr[i] << " ";
    }
    return 0;
}

Drag options to blanks, or click blank then click option'

Ai

Bi < 5

Dj

Attempts:

3 left

💡 Hint

Common Mistakes

Using different variable names in the loop declaration and condition.

Using 'j' instead of 'i' causing errors.

Incorrect loop condition.

The loop variable is 'i', the condition is 'i < 5', and the increment is 'i++'.