Continue statement in C++ - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to skip printing the number 3 in the loop.

C++

#include <iostream>

int main() {
    for (int i = 1; i <= 5; i++) {
        if (i == 3) {
            [1];
        }
        std::cout << i << " ";
    }
    return 0;
}

Drag options to blanks, or click blank then click option'

Acontinue

Bbreak

Creturn

Dexit

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'break' instead of 'continue' which stops the loop completely.

Using 'return' which exits the whole function.

Using 'exit' which ends the program.

The 'continue' statement skips the current iteration and moves to the next one, so number 3 is not printed.

2fill in blank

medium

Complete the code to skip all even numbers in the loop.

C++

#include <iostream>

int main() {
    for (int i = 1; i <= 6; i++) {
        if (i % 2 == 0) {
            [1];
        }
        std::cout << i << " ";
    }
    return 0;
}

Drag options to blanks, or click blank then click option'

Aexit

Bcontinue

Creturn

Dbreak

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'break' which stops the loop entirely.

Using 'return' which exits the function.

Using 'exit' which ends the program.

The 'continue' statement skips printing even numbers by moving to the next iteration.

3fill in blank

hard

Fix the error in the code to correctly skip printing negative numbers.

C++

#include <iostream>

int main() {
    int numbers[] = {2, -1, 3, -4, 5};
    for (int i = 0; i < 5; i++) {
        if (numbers[i] < 0) {
            [1];
        }
        std::cout << numbers[i] << " ";
    }
    return 0;
}

Drag options to blanks, or click blank then click option'

Aexit

Bbreak

Creturn

Dcontinue

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'break' which stops the loop completely.

Using 'return' which exits the function.

Using 'exit' which ends the program.

Using 'continue' skips printing negative numbers and continues the loop.

4fill in blank

hard

Fill both blanks to skip printing multiples of 3 and continue the loop.

C++

#include <iostream>

int main() {
    for (int i = 1; i <= 10; i++) {
        if (i [1] 3 [2] 0) {
            continue;
        }
        std::cout << i << " ";
    }
    return 0;
}

Drag options to blanks, or click blank then click option'

A%

B==

C!=

D/

Attempts:

3 left

💡 Hint

Common Mistakes

Using '/' instead of '%' for modulus.

Using '!=' instead of '==' in the condition.

Using 'break' instead of 'continue'.

The condition 'i % 3 == 0' checks for multiples of 3, and 'continue' skips printing them.

5fill in blank

hard

Fill all three blanks to skip printing numbers less than 5 and continue the loop.

C++

#include <iostream>

int main() {
    int arr[] = {2, 5, 7, 3, 8};
    for (int [1] = 0; [2]; [3]++) {
        if (arr[i] < 5) {
            continue;
        }
        std::cout << arr[i] << " ";
    }
    return 0;
}

Drag options to blanks, or click blank then click option'

Ai

Bi < 5

Dj

Attempts:

3 left

💡 Hint

Common Mistakes

Using different variable names in the loop declaration and condition.

Using 'j' instead of 'i' causing errors.

Incorrect loop condition.

The loop variable is 'i', the condition is 'i < 5', and the increment is 'i++'.

Practice

1. What does the continue statement do inside a loop in C++?

easy

A. It stops the entire loop immediately.

B. It skips the rest of the current loop iteration and moves to the next iteration.

C. It exits the current function.

D. It restarts the program from the beginning.

Solution

1. Step 1: Understand the role of continue in loops

   The continue statement tells the program to skip the remaining code in the current loop cycle.

2. Step 2: Identify what happens after continue

   After skipping, the loop moves to the next iteration immediately without executing the rest of the loop body.

3. Final Answer:

   It skips the rest of the current loop iteration and moves to the next iteration. -> Option B

4. Quick Check:

   Continue skips current iteration [OK]

Hint: Continue skips current loop step, not whole loop [OK]

Common Mistakes:

• Thinking continue stops the loop completely
• Confusing continue with break
• Assuming continue exits the function

2. Which of the following is the correct syntax to use continue inside a for loop in C++?

easy

A. continue;

B. continue()

C. continue{}

D. continue[]

Solution

1. Step 1: Recall the syntax of continue in C++

   The continue statement is a keyword and used alone followed by a semicolon.

2. Step 2: Check each option's syntax

   Only continue; is valid. The others use parentheses or braces which are incorrect.

3. Final Answer:

   continue; -> Option A

4. Quick Check:

   Continue ends with semicolon [OK]

Hint: Continue is a keyword, ends with semicolon [OK]

Common Mistakes:

• Adding parentheses after continue
• Using braces or brackets with continue
• Omitting the semicolon

3. What will be the output of the following C++ code?

for (int i = 1; i <= 5; i++) {
    if (i == 3) continue;
    std::cout << i << " ";
}

medium

A. 1 2 3 4 5

B. 1 2 3 4

C. 1 2 4 5

D. 2 3 4 5

Solution

1. Step 1: Analyze the loop and condition

   The loop runs from 1 to 5. When i == 3, the continue skips printing.

2. Step 2: Determine printed values

   Numbers 1 and 2 print normally. At 3, continue skips printing. Then 4 and 5 print.

3. Final Answer:

   1 2 4 5 -> Option C

4. Quick Check:

   Skip 3, print others [OK]

Hint: Continue skips printing 3, others print [OK]

Common Mistakes:

• Including 3 in output
• Stopping loop at 3
• Printing numbers after 3 incorrectly

4. Identify the error in the following C++ code snippet:

for (int i = 0; i < 5; i++) {
    if (i == 2)
        continue
    std::cout << i << " ";
}

medium

A. No error in the code.

B. Incorrect loop condition.

C. Wrong variable type for i.

D. Missing semicolon after continue statement.

Solution

1. Step 1: Check syntax of continue statement

   The continue statement must end with a semicolon.

2. Step 2: Identify missing semicolon

   In the code, continue is not followed by a semicolon, causing a syntax error.

3. Final Answer:

   Missing semicolon after continue statement. -> Option D

4. Quick Check:

   Continue needs semicolon [OK]

Hint: Always put semicolon after continue [OK]

Common Mistakes:

• Forgetting semicolon after continue
• Assuming continue needs parentheses
• Misreading loop condition as error

5. Consider the following code that sums numbers from 1 to 10 but skips multiples of 3 using continue. What is the final sum?

int sum = 0;
for (int i = 1; i <= 10; i++) {
    if (i % 3 == 0) continue;
    sum += i;
}
std::cout << sum;

hard

A. 52

B. 55

C. 45

D. 50

Solution

1. Step 1: Identify numbers skipped by continue

   Numbers divisible by 3 (3, 6, 9) are skipped and not added to sum.

2. Step 2: Calculate sum of numbers 1 to 10 excluding 3, 6, 9

   Sum 1+2+4+5+7+8+10 = 37 + 15 = 52

3. Final Answer:

   52 -> Option A

4. Quick Check:

   Sum excluding multiples of 3 = 52 [OK]

Hint: Skip multiples of 3, sum others [OK]

Common Mistakes:

• Including multiples of 3 in sum
• Adding all numbers 1 to 10
• Misunderstanding continue effect