Continue statement in C++ - Practice Problems & Coding Challenges

Challenge - 5 Problems

❓ Predict Output

intermediate

Output of loop with continue

What is the output of the following C++ code?

C++

#include <iostream>
int main() {
    for (int i = 1; i <= 5; i++) {
        if (i == 3) continue;
        std::cout << i << " ";
    }
    return 0;
}

A 1 2 4 5

B 2 3 4 5

C 1 2 3 4

D 1 2 3 4 5

💡 Hint

The continue statement skips the rest of the loop body for the current iteration.

When i equals 3, the continue statement skips printing 3 and moves to the next iteration. So the output excludes 3.

❓ Predict Output

intermediate

Sum with continue skipping multiples of 4

What is the value of sum after running this code?

C++

#include <iostream>
int main() {
    int sum = 0;
    for (int i = 1; i <= 10; i++) {
        if (i % 4 == 0) continue;
        sum += i;
    }
    std::cout << sum;
    return 0;
}

A 43

B 50

C 40

D 55

💡 Hint

Numbers divisible by 4 are skipped and not added to sum.

Numbers 4 and 8 are skipped. Sum of 1+2+3+5+6+7+9+10 = 43.

❓ Predict Output

advanced

Nested loops with continue

What is the output of this nested loop code?

C++

#include <iostream>
int main() {
    for (int i = 1; i <= 3; i++) {
        for (int j = 1; j <= 3; j++) {
            if (j == 2) continue;
            std::cout << i << j << " ";
        }
    }
    return 0;
}

A 12 22 32

B 11 12 13 21 22 23 31 32 33

C 11 13 22 23 31 33

D 11 13 21 23 31 33

💡 Hint

The continue skips printing when j equals 2 inside inner loop.

For each i, j=2 is skipped, so only j=1 and j=3 print. Output is pairs: 11 13 21 23 31 33.

❓ Predict Output

advanced

Continue in while loop

What is the output of this code?

C++

#include <iostream>
int main() {
    int i = 0;
    while (i < 5) {
        i++;
        if (i == 3) continue;
        std::cout << i << " ";
    }
    return 0;
}

A 1 2 3 4 5

B 1 2 4 5

C 2 3 4 5

D 1 2 3 4

💡 Hint

The continue skips printing when i equals 3 after increment.

When i is 3, continue skips printing 3. So output excludes 3.

🧠 Conceptual

expert

Effect of continue on loop variable increment

Consider this code snippet. What will be the output?

C++

#include <iostream>
int main() {
    for (int i = 0; i < 5; ) {
        i++;
        if (i == 3) continue;
        std::cout << i << " ";
    }
    return 0;
}

A 1 2 3 4 5

B 1 2 3 4

C 1 2 4 5

D 2 3 4 5

💡 Hint

The increment is inside the loop body before continue.

i is incremented before continue, so when i == 3, continue skips printing 3. Output excludes 3.