Break statement in C++ - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to exit the loop when the number is 5.

C++

#include <iostream>

int main() {
    for (int i = 1; i <= 10; ++i) {
        if (i == 5) {
            [1];
        }
        std::cout << i << " ";
    }
    return 0;
}

Drag options to blanks, or click blank then click option'

Abreak

Bcontinue

Creturn

Dexit

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'continue' instead of 'break' will skip the current iteration but not exit the loop.

Using 'return' will exit the entire function, not just the loop.

The break statement immediately exits the loop when i equals 5.

2fill in blank

medium

Complete the code to stop the while loop when the input number is negative.

C++

#include <iostream>

int main() {
    int num;
    while (true) {
        std::cin >> num;
        if (num < 0) {
            [1];
        }
        std::cout << "Number: " << num << std::endl;
    }
    return 0;
}

Drag options to blanks, or click blank then click option'

Aexit

Bbreak

Ccontinue

Dreturn

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'continue' will skip printing but not stop the loop.

Using 'exit' will terminate the whole program immediately.

The break statement exits the infinite while loop when a negative number is entered.

3fill in blank

hard

Fix the error in the code to exit the loop when the character 'q' is entered.

C++

#include <iostream>

int main() {
    char ch;
    while (true) {
        std::cin >> ch;
        if (ch == 'q') {
            [1];
        }
        std::cout << ch << std::endl;
    }
    return 0;
}

Drag options to blanks, or click blank then click option'

Areturn 0

Bcontinue

Cbreak

Dexit(0)

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'continue' will skip printing but not exit the loop.

Using 'return 0' or 'exit(0)' will end the program, not just the loop.

The break statement exits the loop when the user inputs 'q'.

4fill in blank

hard

Fill both blanks to create a loop that prints numbers 1 to 10 but stops at 7.

C++

#include <iostream>

int main() {
    for (int i = 1; i <= [1]; ++i) {
        if (i == [2]) {
            break;
        }
        std::cout << i << " ";
    }
    return 0;
}

Drag options to blanks, or click blank then click option'

A10

B7

C5

D15

Attempts:

3 left

💡 Hint

Common Mistakes

Setting the break condition outside the loop range.

Using the wrong upper limit for the loop.

The loop runs from 1 to 10, but breaks when i equals 7, stopping the loop early.

5fill in blank

hard

Fill all three blanks to create a loop that prints numbers 1 to 20 but stops at the first number divisible by 8.

C++

#include <iostream>

int main() {
    for (int num = 1; num <= [1]; ++num) {
        if (num % [2] == 0) {
            [3];
        }
        std::cout << num << " ";
    }
    return 0;
}

Drag options to blanks, or click blank then click option'

A20

B8

Cbreak

D10

Attempts:

3 left

💡 Hint

Common Mistakes

Using the wrong divisor in the condition.

Not using 'break' to exit the loop.

The loop runs from 1 to 20, and breaks when it finds the first number divisible by 8.

Practice

1.

What does the break statement do inside a loop in C++?

easy

A. It skips the current iteration and continues.

B. It pauses the loop until user input.

C. It restarts the loop from the beginning.

D. It immediately exits the loop.

Solution

1. Step 1: Understand the role of break in loops

   The break statement is used to stop the loop immediately when executed.

2. Step 2: Compare with other loop controls

   Unlike continue which skips to the next iteration, break exits the loop completely.

3. Final Answer:

   It immediately exits the loop. -> Option D

4. Quick Check:

   Break stops loop = exit loop [OK]

Hint: Break means stop loop now, not skip or pause [OK]

Common Mistakes:

• Confusing break with continue
• Thinking break pauses instead of exits
• Assuming break restarts the loop

2.

Which of the following is the correct syntax to use break inside a for loop in C++?

for (int i = 0; i < 5; i++) {
    if (i == 3) {
        ?
    }    // other code
}

easy

A. stop;

B. break;

C. exit;

D. continue;

Solution

1. Step 1: Recall the keyword to exit loops

   The keyword to exit a loop immediately in C++ is break;.

2. Step 2: Check other options for correctness

   stop; and exit; are invalid here, and continue; skips iteration, not exit.

3. Final Answer:

   break; -> Option B

4. Quick Check:

   Use break; to exit loops [OK]

Hint: Break always ends loop, continue skips iteration [OK]

Common Mistakes:

• Using continue instead of break
• Writing stop or exit which are invalid here
• Missing semicolon after break

3.

What is the output of the following C++ code?

for (int i = 1; i <= 5; i++) {
    if (i == 3) {
        break;
    }
    std::cout << i << " ";
}

medium

A. 3 4 5

B. 1 2 3 4 5

C. 1 2

D. No output

Solution

1. Step 1: Trace the loop iterations

   The loop starts with i=1, prints 1, then i=2, prints 2.

2. Step 2: Check the break condition

   When i becomes 3, the if condition is true and break stops the loop immediately, so 3 is not printed.

3. Final Answer:

   1 2 -> Option C

4. Quick Check:

   Break stops loop before printing 3 [OK]

Hint: Break stops before printing the break condition value [OK]

Common Mistakes:

• Including the break value in output
• Ignoring break and printing all
• Confusing break with continue

4.

Identify the error in this C++ code snippet using break:

int i = 0;
if (i == 0) {
    break;
}

medium

A. break cannot be used outside loops or switch.

B. Missing semicolon after break.

C. Variable i is not declared.

D. If condition syntax is wrong.

Solution

1. Step 1: Check where break is used

   The break statement is inside an if but not inside a loop or switch.

2. Step 2: Understand break usage rules

   In C++, break can only be used inside loops or switch statements, not standalone in if.

3. Final Answer:

   break cannot be used outside loops or switch. -> Option A

4. Quick Check:

   Break only inside loops/switch [OK]

Hint: Break only works inside loops or switch blocks [OK]

Common Mistakes:

• Using break in if without loop
• Forgetting break scope rules
• Assuming break works like return

5.

Consider this nested loop code:

for (int i = 1; i <= 3; i++) {
    for (int j = 1; j <= 3; j++) {
        if (j == 2) {
            break;
        }
        std::cout << i << j << " ";
    }
}

What is the output?

hard

A. 11 21 31

B. 11 12 13 21 22 23 31 32 33

C. 11 12 21 22 31 32

D. 11 21 22 31 32

Solution

1. Step 1: Analyze inner loop behavior

   The inner loop runs j=1 to 3, but breaks when j==2, so it only prints when j=1.

2. Step 2: Trace outer loop iterations

   For i=1, prints 11; i=2 prints 21; i=3 prints 31. No other j values print due to break.

3. Final Answer:

   11 21 31 -> Option A

4. Quick Check:

   Break stops inner loop at j=2, prints only j=1 [OK]

Hint: Break stops inner loop early, only first j prints per i [OK]

Common Mistakes:

• Assuming all j values print
• Confusing break effect on outer loop
• Ignoring break inside nested loops