Break statement in C++ - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to exit the loop when the number is 5.

C++

#include <iostream>

int main() {
    for (int i = 1; i <= 10; ++i) {
        if (i == 5) {
            [1];
        }
        std::cout << i << " ";
    }
    return 0;
}

Drag options to blanks, or click blank then click option'

Abreak

Bcontinue

Creturn

Dexit

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'continue' instead of 'break' will skip the current iteration but not exit the loop.

Using 'return' will exit the entire function, not just the loop.

The break statement immediately exits the loop when i equals 5.

2fill in blank

medium

Complete the code to stop the while loop when the input number is negative.

C++

#include <iostream>

int main() {
    int num;
    while (true) {
        std::cin >> num;
        if (num < 0) {
            [1];
        }
        std::cout << "Number: " << num << std::endl;
    }
    return 0;
}

Drag options to blanks, or click blank then click option'

Aexit

Bbreak

Ccontinue

Dreturn

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'continue' will skip printing but not stop the loop.

Using 'exit' will terminate the whole program immediately.

The break statement exits the infinite while loop when a negative number is entered.

3fill in blank

hard

Fix the error in the code to exit the loop when the character 'q' is entered.

C++

#include <iostream>

int main() {
    char ch;
    while (true) {
        std::cin >> ch;
        if (ch == 'q') {
            [1];
        }
        std::cout << ch << std::endl;
    }
    return 0;
}

Drag options to blanks, or click blank then click option'

Areturn 0

Bcontinue

Cbreak

Dexit(0)

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'continue' will skip printing but not exit the loop.

Using 'return 0' or 'exit(0)' will end the program, not just the loop.

The break statement exits the loop when the user inputs 'q'.

4fill in blank

hard

Fill both blanks to create a loop that prints numbers 1 to 10 but stops at 7.

C++

#include <iostream>

int main() {
    for (int i = 1; i <= [1]; ++i) {
        if (i == [2]) {
            break;
        }
        std::cout << i << " ";
    }
    return 0;
}

Drag options to blanks, or click blank then click option'

A10

B7

C5

D15

Attempts:

3 left

💡 Hint

Common Mistakes

Setting the break condition outside the loop range.

Using the wrong upper limit for the loop.

The loop runs from 1 to 10, but breaks when i equals 7, stopping the loop early.

5fill in blank

hard

Fill all three blanks to create a loop that prints numbers 1 to 20 but stops at the first number divisible by 8.

C++

#include <iostream>

int main() {
    for (int num = 1; num <= [1]; ++num) {
        if (num % [2] == 0) {
            [3];
        }
        std::cout << num << " ";
    }
    return 0;
}

Drag options to blanks, or click blank then click option'

A20

B8

Cbreak

D10

Attempts:

3 left

💡 Hint

Common Mistakes

Using the wrong divisor in the condition.

Not using 'break' to exit the loop.

The loop runs from 1 to 20, and breaks when it finds the first number divisible by 8.