Break statement in C++ - Practice Problems & Coding Challenges

Challenge - 5 Problems

❓ Predict Output

intermediate

Output of break in a for loop

What is the output of this C++ code snippet?

C++

#include <iostream>
int main() {
    for (int i = 0; i < 5; i++) {
        if (i == 3) {
            break;
        }
        std::cout << i << " ";
    }
    return 0;
}

A 0 1 2 3

B 0 1 2 3 4

C 3 4

D 0 1 2

💡 Hint

The break statement stops the loop when i equals 3.

The loop prints numbers starting from 0. When i reaches 3, break stops the loop, so only 0, 1, and 2 are printed.

❓ Predict Output

intermediate

Break inside nested loops

What is the output of this C++ code?

C++

#include <iostream>
int main() {
    for (int i = 0; i < 3; i++) {
        for (int j = 0; j < 3; j++) {
            if (j == 1) {
                break;
            }
            std::cout << i << j << " ";
        }
    }
    return 0;
}

A 00 10 20

B 00 01 10 11 20 21

C 00 10 20 21 22

D 00 01 02 10 11 12 20 21 22

💡 Hint

Break stops the inner loop when j equals 1.

The inner loop prints j=0 then breaks when j=1, so for each i, only i0 is printed.

❓ Predict Output

advanced

Break in while loop with condition

What is the output of this C++ program?

C++

#include <iostream>
int main() {
    int count = 0;
    while (true) {
        if (count == 4) {
            break;
        }
        std::cout << count << " ";
        count++;
    }
    return 0;
}

A 0 1 2 3 4 5

B 0 1 2 3 4

C 0 1 2 3

D 1 2 3 4

💡 Hint

Break stops the loop when count reaches 4, so 4 is not printed.

The loop prints count starting at 0. When count equals 4, break stops the loop before printing 4.

❓ Predict Output

advanced

Break effect on switch-case

What is the output of this C++ code?

C++

#include <iostream>
int main() {
    int x = 2;
    switch (x) {
        case 1:
            std::cout << "One ";
            break;
        case 2:
            std::cout << "Two ";
            break;
        case 3:
            std::cout << "Three ";
        default:
            std::cout << "Default ";
    }
    return 0;
}

A One Two

B Two

C Two Default

D One Two Default

💡 Hint

Break stops execution after printing "Two ".

Switch starts at case 2, prints "Two ", then break stops further cases from running.

🧠 Conceptual

expert

Break statement behavior in nested loops

Consider this C++ code snippet. Which statement is true about the effect of the break statement inside the inner loop?

C++

#include <iostream>
int main() {
    for (int i = 0; i < 3; i++) {
        for (int j = 0; j < 3; j++) {
            if (i == j) {
                break;
            }
            std::cout << i << j << " ";
        }
    }
    return 0;
}

A The break stops only the inner loop when i equals j, outer loop continues.

B The break stops both inner and outer loops immediately when i equals j.

C The break causes a compile-time error because it is inside nested loops.

D The break stops the outer loop only, inner loop continues.

💡 Hint

Break affects only the loop it is directly inside.

Break stops the closest enclosing loop, here the inner loop. The outer loop continues normally.

Practice

1.

What does the break statement do inside a loop in C++?

easy

A. It skips the current iteration and continues.

B. It pauses the loop until user input.

C. It restarts the loop from the beginning.

D. It immediately exits the loop.

Solution

1. Step 1: Understand the role of break in loops

   The break statement is used to stop the loop immediately when executed.

2. Step 2: Compare with other loop controls

   Unlike continue which skips to the next iteration, break exits the loop completely.

3. Final Answer:

   It immediately exits the loop. -> Option D

4. Quick Check:

   Break stops loop = exit loop [OK]

Hint: Break means stop loop now, not skip or pause [OK]

Common Mistakes:

• Confusing break with continue
• Thinking break pauses instead of exits
• Assuming break restarts the loop

2.

Which of the following is the correct syntax to use break inside a for loop in C++?

for (int i = 0; i < 5; i++) {
    if (i == 3) {
        ?
    }    // other code
}

easy

A. stop;

B. break;

C. exit;

D. continue;

Solution

1. Step 1: Recall the keyword to exit loops

   The keyword to exit a loop immediately in C++ is break;.

2. Step 2: Check other options for correctness

   stop; and exit; are invalid here, and continue; skips iteration, not exit.

3. Final Answer:

   break; -> Option B

4. Quick Check:

   Use break; to exit loops [OK]

Hint: Break always ends loop, continue skips iteration [OK]

Common Mistakes:

• Using continue instead of break
• Writing stop or exit which are invalid here
• Missing semicolon after break

3.

What is the output of the following C++ code?

for (int i = 1; i <= 5; i++) {
    if (i == 3) {
        break;
    }
    std::cout << i << " ";
}

medium

A. 3 4 5

B. 1 2 3 4 5

C. 1 2

D. No output

Solution

1. Step 1: Trace the loop iterations

   The loop starts with i=1, prints 1, then i=2, prints 2.

2. Step 2: Check the break condition

   When i becomes 3, the if condition is true and break stops the loop immediately, so 3 is not printed.

3. Final Answer:

   1 2 -> Option C

4. Quick Check:

   Break stops loop before printing 3 [OK]

Hint: Break stops before printing the break condition value [OK]

Common Mistakes:

• Including the break value in output
• Ignoring break and printing all
• Confusing break with continue

4.

Identify the error in this C++ code snippet using break:

int i = 0;
if (i == 0) {
    break;
}

medium

A. break cannot be used outside loops or switch.

B. Missing semicolon after break.

C. Variable i is not declared.

D. If condition syntax is wrong.

Solution

1. Step 1: Check where break is used

   The break statement is inside an if but not inside a loop or switch.

2. Step 2: Understand break usage rules

   In C++, break can only be used inside loops or switch statements, not standalone in if.

3. Final Answer:

   break cannot be used outside loops or switch. -> Option A

4. Quick Check:

   Break only inside loops/switch [OK]

Hint: Break only works inside loops or switch blocks [OK]

Common Mistakes:

• Using break in if without loop
• Forgetting break scope rules
• Assuming break works like return

5.

Consider this nested loop code:

for (int i = 1; i <= 3; i++) {
    for (int j = 1; j <= 3; j++) {
        if (j == 2) {
            break;
        }
        std::cout << i << j << " ";
    }
}

What is the output?

hard

A. 11 21 31

B. 11 12 13 21 22 23 31 32 33

C. 11 12 21 22 31 32

D. 11 21 22 31 32

Solution

1. Step 1: Analyze inner loop behavior

   The inner loop runs j=1 to 3, but breaks when j==2, so it only prints when j=1.

2. Step 2: Trace outer loop iterations

   For i=1, prints 11; i=2 prints 21; i=3 prints 31. No other j values print due to break.

3. Final Answer:

   11 21 31 -> Option A

4. Quick Check:

   Break stops inner loop at j=2, prints only j=1 [OK]

Hint: Break stops inner loop early, only first j prints per i [OK]

Common Mistakes:

• Assuming all j values print
• Confusing break effect on outer loop
• Ignoring break inside nested loops