Why functions are needed - Test Your Understanding

Practice - 5 Tasks

1fill in blank

easy

Complete the code to define a function named greet.

C

void [1]() {
    printf("Hello!\n");
}

Drag options to blanks, or click blank then click option'

Aprint

Bmain

Cgreet

Dhello

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'main' instead of the function name.

Using 'print' which is not a valid function name in C.

Using 'hello' which is not the intended function name.

The function name should be greet to match the definition.

2fill in blank

medium

Complete the code to call the function greet inside main.

C

int main() {
    [1]();
    return 0;
}

Drag options to blanks, or click blank then click option'

Agreet

Bhello

Cprint

Dmain

Attempts:

3 left

💡 Hint

Common Mistakes

Calling 'print()' which is not defined.

Calling 'hello()' which is not defined.

Calling 'main()' inside main causes recursion.

To call the function defined as greet, use greet();.

3fill in blank

hard

Fix the error in the function definition by completing the return type.

C

[1] greet() {
    printf("Hello!\n");
}

Drag options to blanks, or click blank then click option'

Avoid

Bint

Cchar

Dfloat

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'int' without a return statement causes warnings.

Using 'char' or 'float' which are incorrect for this function.

The function does not return a value, so its return type should be void.

4fill in blank

hard

Fill both blanks to create a function that adds two numbers and returns the result.

C

[1] add(int a, int b) {
    return a [2] b;
}

Drag options to blanks, or click blank then click option'

Aint

B+

C-

Dvoid

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'void' as return type when a value is returned.

Using '-' instead of '+' for addition.

The function returns an integer, so the return type is int. To add two numbers, use the + operator.

5fill in blank

hard

Fill all three blanks to create a function that checks if a number is even and returns 1 if true, else 0.

C

[1] is_even(int num) {
    if (num [2] 2 == 0) {
        return [3];
    } else {
        return 0;
    }
}

Drag options to blanks, or click blank then click option'

Aint

B%

C1

D==

Attempts:

3 left

💡 Hint

Common Mistakes

Using '==' instead of '%' to check remainder.

Returning 0 instead of 1 when number is even.

The function returns an integer, so use int. To check if a number is even, use the modulus operator % to get the remainder. If remainder is 0, return 1 to indicate true.