Defining structures

Introduction

Structures let you group different pieces of information together under one name. This helps keep related data organized.

When you want to store information about a person, like name, age, and height.

When you need to keep details about a book, such as title, author, and pages.

When you want to group coordinates like x, y, and z in one place.

When you want to pass multiple related values to a function easily.

When you want to create a simple database record with different fields.

Syntax

C

struct StructureName {
    dataType member1;
    dataType member2;
    // more members
};

Use the keyword struct followed by a name and curly braces.

Each member inside has a type and a name, separated by semicolons.

Examples

This defines a structure named Person with a name and age.

C

struct Person {
    char name[50];
    int age;
};

A simple structure to hold 2D coordinates.

C

struct Point {
    int x;
    int y;
};

A structure to store book details.

C

struct Book {
    char title[100];
    char author[50];
    int pages;
};

Sample Program

This program defines a Person structure, creates a variable p1, assigns values, and prints them.

C

#include <stdio.h>

struct Person {
    char name[50];
    int age;
};

int main() {
    struct Person p1;

    // Assign values
    snprintf(p1.name, sizeof(p1.name), "%s", "Alice");
    p1.age = 30;

    // Print values
    printf("Name: %s\n", p1.name);
    printf("Age: %d\n", p1.age);

    return 0;
}

Important Notes

Remember to use struct keyword when declaring variables unless you use typedef.

Strings in C are arrays of characters, so use char name[50]; for names.

Use functions like snprintf or strcpy to assign strings safely.

Summary

Structures group different data types under one name.

Use struct keyword to define them.

Access members with dot . operator on structure variables.

Practice

1. What is the purpose of using struct in C programming?

easy

A. To allocate memory dynamically

B. To create a loop structure

C. To group different data types under one name

D. To define a function

Solution

1. Step 1: Understand the role of struct

   The struct keyword is used to group variables of different types into a single unit.

2. Step 2: Compare with other options

   Options A, B, and C relate to memory allocation, loops, and functions, which are unrelated to struct.

3. Final Answer:

   To group different data types under one name -> Option C

4. Quick Check:

   struct groups data types = D [OK]

Hint: Remember: struct bundles variables like a box [OK]

Common Mistakes:

• Confusing struct with loops or functions
• Thinking struct allocates memory dynamically
• Assuming struct defines a single data type only

2. Which of the following is the correct syntax to define a structure named Person with members int age and char name[20]?

easy

A. struct Person { int age; char name[20]; };

B. struct Person ( int age; char name[20]; );

C. struct Person = { int age; char name[20]; };

D. struct Person: int age; char name[20];

Solution

1. Step 1: Recall correct struct syntax

   Structures are defined using curly braces { } with semicolons after each member.

2. Step 2: Check each option

   struct Person { int age; char name[20]; }; uses correct braces and semicolons. Options B, C, and D use incorrect symbols or missing braces.

3. Final Answer:

   struct Person { int age; char name[20]; }; -> Option A

4. Quick Check:

   Correct struct syntax uses braces and semicolons = A [OK]

Hint: Use braces { } and semicolons ; inside struct [OK]

Common Mistakes:

• Using parentheses instead of braces
• Missing semicolons after members
• Using equal sign or colon incorrectly

3. What will be the output of the following code?

struct Point { int x; int y; } p = {3, 4};
printf("%d %d", p.x, p.y);

medium

A. 0 0

B. 3 4

C. 4 3

D. Compilation error

Solution

1. Step 1: Understand struct initialization

   The struct Point is initialized with p = {3, 4}, so p.x = 3 and p.y = 4.

2. Step 2: Analyze printf output

   The printf prints p.x and p.y in order, so output is "3 4".

3. Final Answer:

   3 4 -> Option B

4. Quick Check:

   p.x=3 and p.y=4 prints as "3 4" [OK]

Hint: Struct members print in order of initialization [OK]

Common Mistakes:

• Mixing order of members in output
• Assuming default zero values
• Thinking code causes compilation error

4. Identify the error in the following code snippet:

struct Car {
  int speed;
  char model[10];
};

struct Car c;
c.speed = 100;
c.model = "Sedan";

medium

A. Cannot assign string directly to array member

B. Missing semicolon after struct definition

C. Incorrect struct keyword usage

D. Variable c not declared

Solution

1. Step 1: Check struct definition and declaration

   The struct is correctly defined and variable c declared.

2. Step 2: Analyze assignment to c.model

   Arrays cannot be assigned directly with = operator; string copy functions like strcpy are needed.

3. Final Answer:

   Cannot assign string directly to array member -> Option A

4. Quick Check:

   Array assignment needs strcpy, not = [OK]

Hint: Use strcpy to assign strings to char arrays [OK]

Common Mistakes:

• Assigning string literals directly to char arrays
• Forgetting to include string.h for strcpy
• Assuming semicolon or declaration errors

5. Given the structure definition:

struct Employee {
  int id;
  char name[30];
  float salary;
};

Which of the following code snippets correctly creates an Employee variable and initializes all members in one statement?

hard

A. struct Employee e; e.id = 101; e.name = "Alice"; e.salary = 75000.0;

B. struct Employee e = {id:101, name:"Alice", salary:75000.0};

C. struct Employee e = (101, "Alice", 75000.0);

D. struct Employee e = {101, "Alice", 75000.0};

Solution

1. Step 1: Check initialization syntax for struct

   Structs can be initialized with braces { } listing values in order of members.

2. Step 2: Evaluate each option

   struct Employee e = {101, "Alice", 75000.0}; uses correct brace initialization. struct Employee e; e.id = 101; e.name = "Alice"; e.salary = 75000.0; tries to assign string directly to array (invalid). struct Employee e = (101, "Alice", 75000.0); uses parentheses incorrectly. struct Employee e = {id:101, name:"Alice", salary:75000.0}; uses named initialization which is not standard in C.

3. Final Answer:

   struct Employee e = {101, "Alice", 75000.0}; -> Option D

4. Quick Check:

   Brace list initialization is correct for structs [OK]

Hint: Use braces with values in order to initialize structs [OK]

Common Mistakes:

• Assigning strings directly to arrays after declaration
• Using parentheses instead of braces
• Trying named member initialization (not standard C)