Why arrays are needed in C - Test Your Understanding

Practice - 5 Tasks

1fill in blank

easy

Complete the code to declare an array of 5 integers.

C

int numbers[[1]];

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A5

B10

C0

D1

Attempts:

3 left

💡 Hint

Common Mistakes

Using zero as the size, which creates an empty array.

Forgetting to specify the size.

The number inside the square brackets specifies the size of the array. Here, 5 means the array can hold 5 integers.

2fill in blank

medium

Complete the code to access the third element of the array.

C

int third = numbers[[1]];

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A2

B3

C1

D0

Attempts:

3 left

💡 Hint

Common Mistakes

Using 3 as the index, which is actually the fourth element.

Confusing 1-based and 0-based indexing.

Array indexing in C starts at 0, so the third element is at index 2.

3fill in blank

hard

Fix the error in the code to initialize an array with values 1 to 5.

C

int numbers[5] = {1, 2, 3, 4, [1];

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A4

B5

C6

D0

Attempts:

3 left

💡 Hint

Common Mistakes

Using a number outside the intended range.

Repeating a previous number.

The array should be initialized with values 1 through 5, so the last value must be 5.

4fill in blank

hard

Fill both blanks to create an array of 4 floats and assign 3.14 to the first element.

C

float [1][[2]];
[1][0] = 3.14;

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Avalues

Bnumbers

C4

D5

Attempts:

3 left

💡 Hint

Common Mistakes

Using a size that does not match the intended number of elements.

Using an invalid variable name.

The array is named 'values' and has size 4. Then we assign 3.14 to the first element.

5fill in blank

hard

Fill all three blanks to declare an integer array named 'scores' of size 3 and assign 100 to the last element.

C

int [1][[2]];
[1][[3]] = 100;

Drag options to blanks, or click blank then click option'

Ascores

B3

C2

D1

Attempts:

3 left

💡 Hint

Common Mistakes

Using the wrong index for the last element.

Mismatch between array size and index.

The array is named 'scores' with size 3. The last element is at index 2 (since indexing starts at 0), so we assign 100 there.