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Cprogramming~5 mins

Static storage class - Time & Space Complexity

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Time Complexity: Static storage class
O(n)
Understanding Time Complexity

Let's see how the static storage class affects the time complexity of a program.

We want to know if using static variables changes how long the program takes as input grows.

Scenario Under Consideration

Analyze the time complexity of the following code snippet.


#include <stdio.h>

void countCalls() {
    static int count = 0;
    count++;
    printf("Called %d times\n", count);
}

int main() {
    for (int i = 0; i < 5; i++) {
        countCalls();
    }
    return 0;
}
    

This code counts how many times the function countCalls is called using a static variable.

Identify Repeating Operations

Identify the loops, recursion, array traversals that repeat.

  • Primary operation: The for loop in main calls countCalls repeatedly.
  • How many times: The loop runs 5 times, so the function is called 5 times.
How Execution Grows With Input

As the number of loop iterations grows, the function calls grow at the same rate.

Input Size (n)Approx. Operations
1010 calls to countCalls
100100 calls to countCalls
10001000 calls to countCalls

Pattern observation: The number of operations grows directly with the input size.

Final Time Complexity

Time Complexity: O(n)

This means the time to run grows in a straight line with the number of times the function is called.

Common Mistake

[X] Wrong: "Using a static variable makes the function run faster or slower depending on input size."

[OK] Correct: The static variable only keeps its value between calls; it does not change how many times the function runs or how long each call takes.

Interview Connect

Understanding how static variables behave helps you explain function behavior clearly and shows you know how storage affects program flow.

Self-Check

"What if the static variable was replaced with a normal local variable? How would the time complexity change?"

Practice

(1/5)
1. What does the static keyword do when used with a variable inside a function in C?
easy
A. Keeps the variable value between function calls
B. Makes the variable global
C. Deletes the variable after the function ends
D. Allows the variable to be accessed from other files

Solution

  1. Step 1: Understand static inside a function

    A static variable inside a function keeps its value even after the function finishes.
  2. Step 2: Compare with other options

    Static does not make variables global or accessible outside the file; it preserves value only inside the function.
  3. Final Answer:

    Keeps the variable value between function calls -> Option A
  4. Quick Check:

    Static inside function = value preserved [OK]
Hint: Static inside function means value stays between calls [OK]
Common Mistakes:
  • Thinking static makes variable global
  • Assuming static deletes variable after function ends
  • Confusing static with extern keyword
2. Which of the following is the correct way to declare a static variable inside a function in C?
easy
A. static count int = 0;
B. static int count = 0;
C. int static count = 0;
D. count static int = 0;

Solution

  1. Step 1: Recall correct static syntax

    The correct syntax places static before the type: static int count = 0;.
  2. Step 2: Check other options

    Other options have wrong order of keywords, which is invalid in C.
  3. Final Answer:

    static int count = 0; -> Option B
  4. Quick Check:

    Static keyword comes before type [OK]
Hint: Static always comes before the type in declaration [OK]
Common Mistakes:
  • Placing static after the variable name
  • Mixing order of keywords
  • Using invalid syntax like 'static count int'
3. What will be the output of the following C code?
void func() {
    static int x = 0;
    x++;
    printf("%d ", x);
}

int main() {
    for(int i = 0; i < 3; i++) {
        func();
    }
    return 0;
}
medium
A. 1 1 1
B. 0 1 2
C. 1 2 3
D. 3 3 3

Solution

  1. Step 1: Understand static variable behavior in func()

    The static variable x is initialized once to 0 and keeps its value between calls.
  2. Step 2: Trace the loop calls

    Each call increments x by 1 and prints it. So outputs are 1, then 2, then 3.
  3. Final Answer:

    1 2 3 -> Option C
  4. Quick Check:

    Static variable increments across calls [OK]
Hint: Static variable keeps incrementing each call [OK]
Common Mistakes:
  • Assuming static resets each call
  • Confusing initial value with printed value
  • Expecting output to be zeros
4. Identify the error in the following code snippet:
void func() {
    static int x;
}

int main() {
    x = 5;
    func();
    return 0;
}
medium
A. No error, code runs fine
B. Missing initialization of static variable x
C. Static variables cannot be declared inside functions
D. Static variable x cannot be assigned outside its function

Solution

  1. Step 1: Check variable scope

    The static variable x is declared inside func(), so it is local to that function.
  2. Step 2: Analyze assignment in main()

    Trying to assign x = 5; in main() causes an error because x is not visible outside func().
  3. Final Answer:

    Static variable x cannot be assigned outside its function -> Option D
  4. Quick Check:

    Static inside function = local scope [OK]
Hint: Static inside function is local, can't access outside [OK]
Common Mistakes:
  • Thinking static variables are global
  • Ignoring variable scope rules
  • Assuming static variables must be initialized
5. Consider two C files: file1.c and file2.c.

In file1.c:
static int count = 0;

void increment() {
    count++;
}

int getCount() {
    return count;
}

In file2.c:
extern int count;

int main() {
    increment();
    printf("%d", getCount());
    return 0;
}

What will happen when you compile and run these files together?
hard
A. Compilation error due to undefined reference to count
B. Prints 1
C. Prints 0
D. Runtime error due to static variable

Solution

  1. Step 1: Understand static at file scope

    The static int count has internal linkage, visible only in file1.c.
  2. Step 2: Function access

    increment() and getCount() are external functions that can access the static count since they are in the same file.
  3. Step 3: Analyze extern usage

    The declaration extern int count; in file2.c expects a global variable count defined elsewhere, but since count is static in file1.c, it is not visible externally, causing a linker error.
  4. Final Answer:

    Compilation error due to undefined reference to count -> Option A
  5. Quick Check:

    Static variables have internal linkage, extern cannot access them [OK]
Hint: Static variables limited to file scope, extern can't access [OK]
Common Mistakes:
  • Assuming static variables are global across files
  • Expecting extern to find static variables
  • Ignoring linker errors
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