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Cprogramming~30 mins

One-dimensional arrays in C - Mini Project: Build & Apply

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Working with One-Dimensional Arrays in C
📖 Scenario: You are helping a small store keep track of the number of items sold each day over a week. You will use a one-dimensional array to store these daily sales numbers.
🎯 Goal: Build a simple C program that stores daily sales in an array, calculates the total sales for the week, and prints the total.
📋 What You'll Learn
Create an integer array named daily_sales with exactly 7 elements representing sales for each day of the week.
Create an integer variable named total_sales to hold the sum of all sales.
Use a for loop with the variable i to iterate over the daily_sales array.
Add each element of daily_sales to total_sales inside the loop.
Print the value of total_sales using printf.
💡 Why This Matters
🌍 Real World
Stores and small businesses often track daily sales to understand their performance and plan inventory.
💼 Career
Knowing how to use arrays and loops is essential for programming tasks involving data collection and processing in many software development jobs.
Progress0 / 4 steps
1
Create the sales array
Create an integer array called daily_sales with these exact values: 5, 8, 6, 7, 10, 9, 4.
C
Hint

Use curly braces {} to list the values inside the array.

2
Create the total sales variable
Create an integer variable called total_sales and set it to 0.
C
Hint

Initialize total_sales to zero before adding values.

3
Sum the sales using a for loop
Use a for loop with the variable i to iterate from 0 to 6 inclusive. Inside the loop, add daily_sales[i] to total_sales.
C
Hint

Use total_sales += daily_sales[i]; inside the loop to add each day's sales.

4
Print the total sales
Use printf to print the text Total sales: followed by the value of total_sales and a newline.
C
Hint

Use printf("Total sales: %d\n", total_sales); to print the result.

Practice

(1/5)
1. What is the starting index of a one-dimensional array in C?
easy
A. 0
B. 1
C. -1
D. Depends on the array size

Solution

  1. Step 1: Understand array indexing in C

    In C, arrays always start indexing from 0, meaning the first element is at index 0.
  2. Step 2: Confirm the starting index

    This is a fixed rule in C and does not depend on array size or other factors.
  3. Final Answer:

    0 -> Option A
  4. Quick Check:

    Array indexing starts at 0 [OK]
Hint: Remember: C arrays always start at zero index [OK]
Common Mistakes:
  • Thinking arrays start at 1 like in some other languages
  • Assuming negative indexes are valid
  • Believing index depends on array size
2. Which of the following is the correct way to declare an integer array of size 5 in C?
easy
A. int arr = 5;
B. int arr();
C. array int arr[5];
D. int arr[5];

Solution

  1. Step 1: Recall C array declaration syntax

    In C, arrays are declared by specifying the type, name, and size in square brackets, like int arr[5];
  2. Step 2: Check each option

    int arr[5]; matches the correct syntax. int arr(); uses parentheses which is for functions. int arr = 5; assigns a single int, not an array. array int arr[5]; uses invalid keyword 'array'.
  3. Final Answer:

    int arr[5]; -> Option D
  4. Quick Check:

    Array declaration uses square brackets [OK]
Hint: Use square brackets for array size in declaration [OK]
Common Mistakes:
  • Using parentheses instead of square brackets
  • Assigning a single value instead of declaring array
  • Using invalid keywords like 'array'
3. What will be the output of the following code?
int arr[3] = {10, 20, 30};
printf("%d", arr[1]);
medium
A. 10
B. 30
C. 20
D. Compilation error

Solution

  1. Step 1: Identify the array elements and indexes

    The array arr has elements: arr[0]=10, arr[1]=20, arr[2]=30.
  2. Step 2: Understand the printf statement

    printf prints the value at arr[1], which is 20.
  3. Final Answer:

    20 -> Option C
  4. Quick Check:

    arr[1] = 20 [OK]
Hint: Remember array index 1 is second element [OK]
Common Mistakes:
  • Confusing index 1 with index 0
  • Expecting output 10 or 30 incorrectly
  • Thinking code causes compilation error
4. Find the error in this code snippet:
int arr[4];
arr[4] = 10;
medium
A. Array index out of bounds
B. Missing semicolon
C. Wrong data type
D. No error

Solution

  1. Step 1: Check array size and indexing

    The array arr has size 4, so valid indexes are 0,1,2,3 only.
  2. Step 2: Identify the invalid index usage

    arr[4] accesses the fifth element, which is outside the array bounds causing undefined behavior.
  3. Final Answer:

    Array index out of bounds -> Option A
  4. Quick Check:

    Index must be less than array size [OK]
Hint: Index must be less than array size [OK]
Common Mistakes:
  • Using index equal to array size
  • Ignoring zero-based indexing
  • Assuming no error for out-of-bounds access
5. Given the array declaration int nums[5] = {1, 2, 3, 4, 5};, which code snippet correctly calculates the sum of all elements?
hard
A. int sum = 0; for(int i = 0; i <= 5; i++) sum += nums[i];
B. int sum = 0; for(int i = 0; i < 5; i++) sum += nums[i];
C. int sum = 0; for(int i = 1; i < 5; i++) sum += nums[i];
D. int sum = 0; for(int i = 0; i < 4; i++) sum += nums[i];

Solution

  1. Step 1: Understand array size and valid indexes

    The array nums has 5 elements with indexes 0 to 4.
  2. Step 2: Analyze each loop condition

    int sum = 0; for(int i = 0; i <= 5; i++) sum += nums[i]; uses i <= 5 which accesses nums[5] (out of bounds). int sum = 0; for(int i = 0; i < 5; i++) sum += nums[i]; uses i < 5 which correctly iterates from 0 to 4. int sum = 0; for(int i = 1; i < 5; i++) sum += nums[i]; starts at 1, missing nums[0]. int sum = 0; for(int i = 0; i < 4; i++) sum += nums[i]; stops at 4, missing nums[4].
  3. Final Answer:

    int sum = 0; for(int i = 0; i < 5; i++) sum += nums[i]; -> Option B
  4. Quick Check:

    Loop from 0 to less than size sums all elements [OK]
Hint: Loop from 0 to less than array size for all elements [OK]
Common Mistakes:
  • Using <= size causing out-of-bounds access
  • Starting loop at 1 missing first element
  • Stopping loop early missing last element
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