Enum usage in C - Practice Problems & Coding Challenges

Challenge - 5 Problems

❓ Predict Output

intermediate

What is the output of this enum code?

Consider the following C code using an enum. What will be printed?

C

#include <stdio.h>
enum Color { RED, GREEN, BLUE };

int main() {
    enum Color c = GREEN;
    printf("%d\n", c);
    return 0;
}

A 1

B 0

C 2

D Compilation error

💡 Hint

By default, enum values start at 0 and increase by 1.

The enum Color assigns RED=0, GREEN=1, BLUE=2. So printing c when it is GREEN prints 1.

❓ Predict Output

intermediate

What value does this enum variable hold?

What value will be printed by this program?

C

#include <stdio.h>
enum Status { OK = 5, WARNING, ERROR };

int main() {
    enum Status s = ERROR;
    printf("%d\n", s);
    return 0;
}

A 5

B 0

C 6

D 7

💡 Hint

Enum values increment from the last explicitly set value.

OK is set to 5, so WARNING is 6, and ERROR is 7. The variable s is ERROR, so it prints 7.

❓ Predict Output

advanced

What happens when printing an enum with a wrong format specifier?

What is the output or error of this code?

C

#include <stdio.h>
enum Level { LOW, MEDIUM, HIGH };

int main() {
    enum Level l = HIGH;
    printf("%c\n", l);
    return 0;
}

A Prints a character with ASCII code 2

B Prints the number 2

C Compilation error due to wrong format specifier

D Runtime error

💡 Hint

Enum values are integers but printing with %c prints the character for that ASCII code.

The enum value HIGH is 2. Using %c prints the character with ASCII code 2, which is a non-printable control character, so it may appear as a strange symbol or nothing.

🧠 Conceptual

advanced

How many items are in this enum?

Given this enum, how many distinct named constants does it contain?

C

enum Days { MON=1, TUE=2, WED=3, THU=4, FRI=5, SAT=6, SUN=7 };

A 0

B 6

C 7

D 8

💡 Hint

Count the number of names listed inside the enum.

There are seven named constants: MON, TUE, WED, THU, FRI, SAT, SUN.

🧠 Conceptual

expert

What error does this enum code produce?

What error will this code cause when compiled?

C

#include <stdio.h>
enum Numbers { ONE, TWO, ONE };

int main() {
    printf("%d\n", ONE);
    return 0;
}

A Prints 0

B Compilation error: duplicate enum constant 'ONE'

C Runtime error

D Compilation error: missing semicolon

💡 Hint

Enum constants must have unique names.

The enum defines 'ONE' twice, which is not allowed and causes a compilation error for duplicate enum constant.

Practice

1. What is the main purpose of using enum in C programming?

easy

A. To give names to integer constants for better code readability

B. To create floating-point variables

C. To define functions

D. To allocate memory dynamically

Solution

1. Step 1: Understand enum usage

   An enum groups related integer constants under meaningful names.

2. Step 2: Identify the purpose

   This helps make code easier to read and maintain by replacing numbers with names.

3. Final Answer:

   To give names to integer constants for better code readability -> Option A

4. Quick Check:

   Enum = Named integer constants [OK]

Hint: Enums name numbers to improve code clarity [OK]

Common Mistakes:

• Thinking enums create variables or functions
• Confusing enums with dynamic memory
• Assuming enums hold floating-point values

2. Which of the following is the correct syntax to declare an enum named Color with values RED, GREEN, and BLUE?

easy

A. enum Color: RED, GREEN, BLUE;

B. enum Color = { RED, GREEN, BLUE };

C. enum Color { RED, GREEN, BLUE };

D. enum Color ( RED, GREEN, BLUE );

Solution

1. Step 1: Recall enum declaration syntax

   In C, enums are declared using the keyword enum, followed by the name and braces with values separated by commas.

2. Step 2: Check each option

   enum Color { RED, GREEN, BLUE }; uses correct syntax: enum Color { RED, GREEN, BLUE };. Others use invalid symbols or assignment.

3. Final Answer:

   enum Color { RED, GREEN, BLUE }; -> Option C

4. Quick Check:

   Correct enum syntax uses braces and commas [OK]

Hint: Use braces {} and commas for enum values [OK]

Common Mistakes:

• Using '=' instead of braces
• Using parentheses instead of braces
• Using colon ':' which is invalid in C enums

3. What will be the output of this C code?

enum Day { SUN, MON, TUE = 5, WED, THU };
#include 
int main() {
    printf("%d %d %d %d %d", SUN, MON, TUE, WED, THU);
    return 0;
}

medium

A. 1 2 5 6 7

B. 5 6 7 8 9

C. 0 1 2 3 4

D. 0 1 5 6 7

Solution

1. Step 1: Understand enum value assignment

   By default, enums start at 0 and increase by 1. Here, SUN=0, MON=1. TUE is explicitly set to 5.

2. Step 2: Calculate following values

   After TUE=5, WED becomes 6, and THU becomes 7 automatically.

3. Final Answer:

   0 1 5 6 7 -> Option D

4. Quick Check:

   Explicit enum values override counting [OK]

Hint: Explicit enum values reset counting from that point [OK]

Common Mistakes:

• Assuming all values auto-increment ignoring explicit assignments
• Starting enum values at 1 by default
• Confusing enum names with strings

4. Identify the error in this enum declaration:

enum Status {
    OK = 1,
    ERROR,
    WARNING = "3"
};

medium

A. Missing semicolon after enum declaration

B. Enum values must be integers, not strings

C. Enum names cannot be uppercase

D. ERROR cannot follow OK without explicit value

Solution

1. Step 1: Check enum value types

   Enum values in C must be integer constants. Here, WARNING is assigned a string "3", which is invalid.

2. Step 2: Verify other syntax

   Semicolon is present, uppercase names are allowed, and ERROR can auto-increment from OK=1.

3. Final Answer:

   Enum values must be integers, not strings -> Option B

4. Quick Check:

   Enum values = integers only [OK]

Hint: Enum values must be integer constants [OK]

Common Mistakes:

• Assigning strings to enum values
• Thinking enum names must be lowercase
• Forgetting semicolon after enum

5. Given this enum and code snippet, what is the output?

enum Flags { FLAG_A = 1 << 0, FLAG_B = 1 << 1, FLAG_C = 1 << 2 };
#include 
int main() {
    int combined = FLAG_A | FLAG_C;
    if (combined & FLAG_B) {
        printf("Flag B set\n");
    } else {
        printf("Flag B not set\n");
    }
    return 0;
}

hard

A. Flag B not set

B. Flag B set

C. Compilation error

D. Flag A and C set

Solution

1. Step 1: Understand bitwise enum values

   FLAG_A = 1 (binary 001), FLAG_B = 2 (010), FLAG_C = 4 (100). Combined = FLAG_A | FLAG_C = 1 | 4 = 5 (binary 101).

2. Step 2: Check if FLAG_B is set in combined

   combined & FLAG_B = 5 & 2 = 0 (binary 101 & 010 = 000), so FLAG_B is not set.

3. Final Answer:

   Flag B not set -> Option A

4. Quick Check:

   Bitwise AND zero means flag not set [OK]

Hint: Use bitwise AND to check if flag is set [OK]

Common Mistakes:

• Assuming combined flags include all bits
• Confusing bitwise OR and AND
• Expecting compilation error due to bit shifts