Array size and bounds in C - Mini Project: Build & Apply

Array size and bounds

📖 Scenario: You are working on a simple program that stores the ages of a small group of friends. You want to make sure you create an array with the right size and access its elements safely.

🎯 Goal: Create an array to hold exactly 5 ages, set a limit variable for the array size, use a loop to print each age, and display the ages one by one.

📋 What You'll Learn

Create an integer array called ages with exactly 5 elements: 21, 25, 30, 22, 28

Create an integer variable called size and set it to the number of elements in ages

Use a for loop with an index variable i from 0 to size - 1 to access each element in ages

Print each age inside the loop using printf

💡 Why This Matters

🌍 Real World

Arrays are used to store lists of data like ages, scores, or measurements in many programs.

💼 Career

Understanding array size and bounds is essential for writing safe and efficient code in software development.

1

Create the array of ages

Create an integer array called ages with exactly 5 elements: 21, 25, 30, 22, and 28.

C

# Create the array called ages with the 5 given values
// Your code here

Need a hint?

Use the syntax int ages[5] = {value1, value2, value3, value4, value5}; to create the array.

2

Set the size variable

Create an integer variable called size and set it to 5, the number of elements in the ages array.

C

int ages[5] = {21, 25, 30, 22, 28};
// Create the size variable and set it to 5
// Your code here

Need a hint?

Just write int size = 5; to store the array length.

3

Loop through the array

Use a for loop with an index variable i starting at 0 and running while i < size. Inside the loop, access each element of ages using ages[i].

C

int ages[5] = {21, 25, 30, 22, 28};
int size = 5;
// Write a for loop to access each element of ages
// Your code here

Need a hint?

Use for (int i = 0; i < size; i++) and inside the loop use ages[i] to get each age.

4

Print each age

Inside the for loop, use printf to print each age in the format: Age: X where X is the current age from ages[i]. Then run the program to see the output.

C

int ages[5] = {21, 25, 30, 22, 28};
int size = 5;
for (int i = 0; i < size; i++) {
    // Print the current age
    // Your code here
}

Need a hint?

Use printf("Age: %d\n", ages[i]); inside the loop to print each age on its own line.