📖 Scenario: Imagine you are organizing a small event and need to count the number of guests entering. You want to stop counting once a certain number is reached to avoid overcrowding.
🎯 Goal: You will write a simple C program that uses loop control to count guests until a maximum limit is reached, demonstrating why controlling loops is important.
📋 What You'll Learn
Create an integer variable called guest_count initialized to 0
Create an integer variable called max_guests and set it to 5
Use a while loop that runs as long as guest_count is less than max_guests
Inside the loop, increment guest_count by 1
Print the current guest_count inside the loop
After the loop, print a message saying "Maximum guests reached"
💡 Why This Matters
🌍 Real World
Counting guests or items and stopping at a limit is common in event management, inventory control, and many other real-life tasks.
💼 Career
Understanding loop control is essential for writing efficient and safe programs that do not run endlessly and handle tasks correctly.
Progress0 / 4 steps
1
Create guest count variables
Create an integer variable called guest_count and set it to 0. Also create an integer variable called max_guests and set it to 5.
C
Hint
Use int guest_count = 0; and int max_guests = 5; inside main().
2
Set up the while loop
Add a while loop that runs as long as guest_count is less than max_guests.
C
Hint
Use while (guest_count < max_guests) to start the loop.
3
Increment guest count and print inside loop
Inside the while loop, increment guest_count by 1 and print the current guest_count using printf.
C
Hint
Use guest_count++; to add one and printf("Guest count: %d\n", guest_count); to print.
4
Print message after loop ends
After the while loop, print the message "Maximum guests reached" using printf.
C
Hint
Use printf("Maximum guests reached\n"); after the loop.
Practice
(1/5)
1. Why is loop control required in C programming?
easy
A. To manage when a loop should stop or skip iterations
B. To declare variables inside the loop
C. To print output inside the loop
D. To define functions inside the loop
Solution
Step 1: Understand loop behavior
Loops repeat code multiple times, so controlling when to stop or skip is important to avoid infinite loops or unwanted actions.
Step 2: Identify the role of loop control
Loop control statements like break and continue help manage loop execution by stopping or skipping iterations.
Final Answer:
To manage when a loop should stop or skip iterations -> Option A
Quick Check:
Loop control = Manage loop flow [OK]
Hint: Loop control manages stopping or skipping loops [OK]
Common Mistakes:
Confusing loop control with variable declaration
Thinking loop control prints output
Assuming loop control defines functions
2. Which of the following is the correct syntax to stop a loop immediately in C?
easy
A. exit;
B. stop;
C. break;
D. continue;
Solution
Step 1: Recall loop control keywords
In C, break; is used to exit a loop immediately.
Step 2: Differentiate from other keywords
continue; skips to next iteration, exit; is not a valid statement, and stop; does not exist.
Final Answer:
break; -> Option C
Quick Check:
Stop loop = break [OK]
Hint: Use 'break;' to stop loops immediately [OK]
Common Mistakes:
Using 'stop;' which is invalid in C
Confusing 'continue;' with stopping the loop
Trying to use 'exit;' as loop control
3. What will be the output of the following C code?
for(int i = 1; i <= 5; i++) {
if(i == 3) {
continue;
}
printf("%d ", i);
}
medium
A. 1 2 3 4 5
B. 1 2 4 5
C. 3 4 5
D. 1 2
Solution
Step 1: Understand the loop and condition
The loop runs from 1 to 5. When i == 3, continue; skips printing 3.
Step 2: Trace output values
Numbers 1, 2 are printed normally. At 3, printing is skipped. Then 4 and 5 are printed.
Final Answer:
1 2 4 5 -> Option B
Quick Check:
Skip 3 with continue = 1 2 4 5 [OK]
Hint: Continue skips current iteration output [OK]
Common Mistakes:
Including 3 in output despite continue
Confusing continue with break
Expecting no output at all
4. Identify the error in the following C code snippet:
int i = 0;
while(i < 5) {
if(i == 3)
break
printf("%d ", i);
i++;
}
medium
A. printf statement syntax error
B. Incorrect use of break inside while loop
C. Variable i is not initialized
D. Missing semicolon after break statement
Solution
Step 1: Check syntax of break statement
The break statement must end with a semicolon (;), but it is missing here.
Step 2: Verify other parts
Variable i is initialized, break is valid inside while, and printf syntax is correct.
Final Answer:
Missing semicolon after break statement -> Option D
Quick Check:
break needs semicolon [OK]
Hint: Always end break with semicolon [OK]
Common Mistakes:
Forgetting semicolon after break
Thinking break can't be inside while
Assuming variable i is uninitialized
5. You want to print all numbers from 1 to 10 except multiples of 3 using a loop in C. Which loop control statement should you use and where?
hard
A. Use continue; when number is multiple of 3 to skip printing
B. Use break; when number is multiple of 3 to stop the loop
C. Use break; after printing multiples of 3
D. Use continue; before the loop starts
Solution
Step 1: Understand the goal
We want to skip printing numbers that are multiples of 3 but continue the loop for others.
Step 2: Choose correct loop control
continue; skips the current iteration, so placing it when number is multiple of 3 skips printing those numbers.
Final Answer:
Use continue; when number is multiple of 3 to skip printing -> Option A
Quick Check:
Skip multiples of 3 = continue [OK]
Hint: Use continue to skip unwanted iterations [OK]
Common Mistakes:
Using break to stop entire loop instead of skipping
Placing continue outside the loop
Trying to break after printing multiples
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