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Cprogramming~5 mins

Operator precedence - Time & Space Complexity

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Time Complexity: Operator precedence
O(1)
Understanding Time Complexity

When we look at operator precedence in C, we want to see how the order of operations affects how many steps the program takes.

We ask: Does the order change how long the program runs as input grows?

Scenario Under Consideration

Analyze the time complexity of the following code snippet.


int compute(int a, int b, int c) {
    int result = a + b * c / 2 - 5;
    return result;
}
    

This code calculates a value using addition, multiplication, division, and subtraction in one line.

Identify Repeating Operations

Identify the loops, recursion, array traversals that repeat.

  • Primary operation: Simple arithmetic operations executed once.
  • How many times: Each operation runs exactly one time per function call.
How Execution Grows With Input

Since the operations happen once, the time does not grow with input size.

Input Size (n)Approx. Operations
104
1004
10004

Pattern observation: The number of steps stays the same no matter how big the inputs are.

Final Time Complexity

Time Complexity: O(1)

This means the program takes the same amount of time no matter the input size.

Common Mistake

[X] Wrong: "Changing the order of operators will make the program slower or faster."

[OK] Correct: Operator order affects calculation results but does not change how many steps the program takes.

Interview Connect

Understanding operator precedence helps you read code clearly and reason about its speed, a useful skill in many programming tasks.

Self-Check

"What if the expression included a loop repeating the calculation n times? How would the time complexity change?"

Practice

(1/5)
1. Which operator has the highest precedence in the expression 3 + 4 * 5?
easy
A. Division (/)
B. Addition (+)
C. Subtraction (-)
D. Multiplication (*)

Solution

  1. Step 1: Recall operator precedence rules

    Multiplication and division have higher precedence than addition and subtraction in C.
  2. Step 2: Identify operators in the expression

    The expression has addition (+) and multiplication (*). Multiplication runs first.
  3. Final Answer:

    Multiplication (*) -> Option D
  4. Quick Check:

    Multiplication > Addition [OK]
Hint: Multiplication and division run before addition and subtraction [OK]
Common Mistakes:
  • Thinking addition runs before multiplication
  • Ignoring operator precedence
  • Assuming left to right always applies
2. Which of the following expressions is correctly written to add 2 and 3, then multiply the result by 4?
easy
A. (2 + 3) * 4
B. 2 + (3 * 4)
C. 2 + 3 * 4
D. 2 * 3 + 4

Solution

  1. Step 1: Understand the desired calculation

    Add 2 and 3 first, then multiply by 4.
  2. Step 2: Check parentheses usage

    Only (2 + 3) * 4 uses parentheses to add 2 and 3 first, then multiply by 4.
  3. Final Answer:

    (2 + 3) * 4 -> Option A
  4. Quick Check:

    Parentheses change order to add first [OK]
Hint: Use parentheses to force addition before multiplication [OK]
Common Mistakes:
  • Ignoring parentheses and trusting default precedence
  • Misreading the expression order
  • Assuming left to right overrides precedence
3. What is the output of this C code?
int x = 5 + 3 * 2 - 4 / 2;
printf("%d", x);
medium
A. 10
B. 9
C. 11
D. 8

Solution

  1. Step 1: Apply operator precedence

    Multiplication and division first: 3 * 2 = 6, 4 / 2 = 2.
  2. Step 2: Calculate the expression left to right

    Expression becomes 5 + 6 - 2 = 9.
  3. Final Answer:

    9 -> Option B
  4. Quick Check:

    5 + 6 - 2 = 9 [OK]
Hint: Calculate * and / before + and - [OK]
Common Mistakes:
  • Adding before multiplying
  • Dividing after subtraction
  • Calculating left to right ignoring precedence
4. Identify the error in this expression:
int result = 10 / 2 * 3 + 4 - 5;
medium
A. Multiplication and division have the same precedence and are left to right
B. Subtraction should be done before multiplication
C. Addition has higher precedence than multiplication
D. Division should be done after addition

Solution

  1. Step 1: Check operator precedence and associativity

    Multiplication (*) and division (/) have the same precedence and are evaluated left to right.
  2. Step 2: Verify the expression evaluation order

    Expression evaluates as ((10 / 2) * 3) + 4 - 5, which is correct.
  3. Final Answer:

    Multiplication and division have the same precedence and are left to right -> Option A
  4. Quick Check:

    * and / same precedence, left to right [OK]
Hint: Remember * and / are equal precedence, evaluated left to right [OK]
Common Mistakes:
  • Thinking division happens after addition
  • Assuming addition has higher precedence
  • Ignoring left-to-right rule for same precedence
5. Given the expression int y = 8 - 3 + 2 * 4 / 2;, which parentheses placement changes the result to 14?
hard
A. 8 - 3 + (2 * 4) / 2
B. 8 - (3 + 2) * 4 / 2
C. (8 - 3 + 2) * 4 / 2
D. (8 - (3 + 2)) * 4 / 2

Solution

  1. Step 1: Calculate original expression

    * and / first left-to-right: 2 * 4 = 8, 8 / 2 = 4; then 8 - 3 + 4 = 9.
  2. Step 2: Evaluate (8 - 3 + 2) * 4 / 2

    (8 - 3 + 2) = 7, 7 * 4 = 28, 28 / 2 = 14.
  3. Step 3: Confirm others

    8 - (3 + 2) * 4 / 2 = 8 - 20 / 2 = 8 - 10 = -2; 8 - 3 + (2 * 4) / 2 = 9; (8 - (3 + 2)) * 4 / 2 = 3 * 4 / 2 = 6.
  4. Final Answer:

    (8 - 3 + 2) * 4 / 2 -> Option C
  5. Quick Check:

    Parentheses force addition before multiplication [OK]
Hint: Try parentheses around addition to change multiplication order [OK]
Common Mistakes:
  • Assuming original order always applies
  • Not recalculating expression after adding parentheses
  • Misplacing parentheses without recalculating
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