You want to print a multiplication table from 1 to 5 using nested loops. Which code snippet correctly achieves this?

hard📝 Application Q8 of 15

C - Loops

Afor(int i=1; i<=5; i++) { for(int j=1; j<=5; j++) printf("%d ", i+j); printf("\n"); }

Bfor(int i=1; i<=5; i++) { for(int j=1; j<=5; j++) { printf("%d ", i-j); } printf("\n"); }

Cfor(int i=1; i<=5; i++) { for(int j=1; j<=5; j++) { printf("%d ", i*j); } printf("\n"); }

Dfor(int i=1; i<=5; i++) { for(int j=1; j<=5; j++) { printf("%d ", i/j); } printf("\n"); }

Step-by-Step Solution

Solution:

Step 1: Understand multiplication table logic
Each cell is product of row and column numbers (i*j).
Step 2: Check code snippets for correct calculation
Only for(int i=1; i<=5; i++) { for(int j=1; j<=5; j++) { printf("%d ", i*j); } printf("\n"); } prints i*j; others print sums, differences, or divisions.
Final Answer:
for(int i=1; i<=5; i++) { for(int j=1; j<=5; j++) { printf("%d ", i*j); } printf("\n"); } -> Option C
Quick Check:
Multiplication table needs i*j product [OK]

Quick Trick: Multiply indices for multiplication table [OK]

Common Mistakes:

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