[Solved] Identify the error in this C loop control code:for(int i = 0; i — Ans: Missing semicolon after break statement | C

C - Loop Control Statements

Identify the error in this C loop control code:

for(int i = 0; i < 5; i++) {
  if(i == 2) break;
  printf("%d ", i);
}

AVariable i is not declared

BIncorrect loop condition

Cprintf statement is outside the loop

DMissing semicolon after break statement

Step-by-Step Solution

Solution:

Step 1: Check syntax of break
In C, break must be followed by a semicolon.
Step 2: Inspect given code
The break statement lacks a semicolon after it.
Step 3: Confirm other parts
Loop condition and variable declaration are correct; printf is inside the loop.
Final Answer:
Missing semicolon after break statement -> Option D
Quick Check:
break must end with semicolon [OK]

Quick Trick: Always end break with semicolon [OK]

Common Mistakes:

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