[Solved] Find the problem in this code snippet:for (int i = 0; i — Ans: Missing semicolon after printf statement. | C

C - Loops

Find the problem in this code snippet:

for (int i = 0; i < 3; i++)
    printf("%d ", i)

AIncorrect loop condition syntax.

BMissing semicolon after printf statement.

CVariable i not declared.

DMissing braces around loop body.

Step-by-Step Solution

Solution:

Step 1: Check syntax of printf line
The printf statement lacks a semicolon at the end, causing a syntax error.
Step 2: Confirm other parts are correct
Loop condition and variable declaration are correct; braces optional for single statement.
Final Answer:
Missing semicolon after printf statement. -> Option B
Quick Check:
Every statement needs semicolon [OK]

Quick Trick: Don't forget semicolon after statements [OK]

Common Mistakes:

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