[Solved] Identify the error in this C code snippet:int main() { int x = 10 printf("%d", x); return 0; } — Ans: Missing semicolon after variable declaration | C

C - Basics and Execution Environment

Identify the error in this C code snippet:

int main() {
    int x = 10
    printf("%d", x);
    return 0;
}

AMissing semicolon after variable declaration

BIncorrect printf format specifier

CVariable x is not declared

DMissing return statement

Step-by-Step Solution

Solution:

Step 1: Check syntax line by line
The line int x = 10 is missing a semicolon at the end, which is required in C.
Step 2: Verify other parts
The printf format specifier %d matches the integer variable, variable x is declared, and return statement is present.
Final Answer:
Missing semicolon after variable declaration -> Option A
Quick Check:
Semicolon missing after int x = 10 [OK]

Quick Trick: Check for missing semicolons after statements [OK]

Common Mistakes:

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