Nested conditional statements - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to check if a number is positive.

C

if (num [1] 0) {
    printf("Positive number\n");
}

Drag options to blanks, or click blank then click option'

A<

B>

C==

D!=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' instead of '>' will check for negative numbers.

Using '==' checks for equality, not positivity.

The condition 'num > 0' checks if the number is positive.

2fill in blank

medium

Complete the code to check if a number is negative.

C

if (num [1] 0) {
    printf("Negative number\n");
}

Drag options to blanks, or click blank then click option'

A>

B!=

C==

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using '>' instead of '<' will check for positive numbers.

Using '==' checks for equality, not negativity.

The condition 'num < 0' checks if the number is negative.

3fill in blank

hard

Fix the error in the nested if statement to check if a number is zero.

C

if (num > 0) {
    printf("Positive\n");
} else if (num [1] 0) {
    printf("Zero\n");
} else {
    printf("Negative\n");
}

Drag options to blanks, or click blank then click option'

A!=

B<

C==

D>

Attempts:

3 left

💡 Hint

Common Mistakes

Using '>' or '<' instead of '==' will not correctly check for zero.

Using '!=' checks for not equal, which is incorrect here.

To check if num is zero, use 'num == 0' in the else if condition.

4fill in blank

hard

Fill both blanks to complete the nested if-else that prints if a number is positive even or odd.

C

if (num [1] 0) {
    if (num [2] 2 == 0) {
        printf("Positive even\n");
    } else {
        printf("Positive odd\n");
    }
}

Drag options to blanks, or click blank then click option'

A>

B<

C%

D==

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' instead of '>' for positivity check.

Using '==' instead of '%' for even check.

First check if num > 0, then use 'num % 2 == 0' to check evenness.

5fill in blank

hard

Fill all three blanks to complete the nested if-else that categorizes a number as positive even, positive odd, or non-positive.

C

if (num [1] 0) {
    if (num [2] 2 [3] 0) {
        printf("Positive even\n");
    } else {
        printf("Positive odd\n");
    }
} else {
    printf("Non-positive number\n");
}

Drag options to blanks, or click blank then click option'

A>

B%

C==

D<=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<=' instead of '>' for positivity check.

Using '!=' instead of '==' for even check.

Check if num > 0, then use 'num % 2 == 0' to check evenness, else non-positive.