An if–else statement lets the program choose between two paths: one if a condition is true, and another if it is false.
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beginner
Write the basic syntax of an if–else statement in C.
if (condition) {
// code if condition is true
} else {
// code if condition is false
}
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beginner
What happens if the condition in an if statement is false and there is no else block?
The program skips the if block and continues with the next code after it, doing nothing inside the if block.
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intermediate
Can you have multiple else if blocks in C? What is their purpose?
Yes, multiple else if blocks let you check several conditions one after another, running the code for the first true condition.
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beginner
Explain with an example how if–else helps in decision making.
Example: if (score >= 50) {
printf("Pass\n");
} else {
printf("Fail\n");
}
This checks if score is 50 or more to print Pass, otherwise prints Fail.
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What will the following code print if x = 10?
if (x > 5) {
printf("Yes");
} else {
printf("No");
}
AError
BNo
CNothing
DYes
✗ Incorrect
Since 10 is greater than 5, the condition is true, so it prints "Yes".
Which keyword is used to check an additional condition after an if in C?
Aelse if
Belseif
Celif
Delse
✗ Incorrect
In C, the correct keyword is "else if" (two words).
What happens if the condition in an if statement is false and there is no else block?
AProgram crashes
BThe if block is skipped
CThe else block runs
DThe program asks for input
✗ Incorrect
If the condition is false and no else block exists, the program skips the if block and continues.
Which of these is a valid if–else syntax in C?
Aif condition then { } else { }
Bif condition { } else { }
Cif (condition) { } else { }
Dif (condition) then { } else { }
✗ Incorrect
In C, conditions must be inside parentheses: if (condition) { } else { }
Can an if statement exist without an else block?
AYes, else is optional
BNo, else is mandatory
COnly if the condition is true
DOnly if the condition is false
✗ Incorrect
The else block is optional; you can have just an if statement.
Explain how an if–else statement controls the flow of a program.
Think about how the program chooses what to do next based on a question.
You got /4 concepts.
Write a simple if–else statement in C that prints "Even" if a number is even, and "Odd" if it is odd.
Use number % 2 to check if remainder is zero.
You got /4 concepts.
Practice
(1/5)
1. What does an if-else statement do in C?
easy
A. It declares a variable.
B. It repeats a block of code multiple times.
C. It defines a new function.
D. It chooses between two actions based on a condition.
Solution
Step 1: Understand the purpose of if-else
An if-else statement lets the program pick one of two paths depending on whether a condition is true or false.
Step 2: Match the description to the options
Only It chooses between two actions based on a condition. describes choosing between two actions based on a condition, which is exactly what if-else does.
Final Answer:
It chooses between two actions based on a condition. -> Option D
Quick Check:
If-else = choose between two paths [OK]
Hint: If you want two choices, use if-else [OK]
Common Mistakes:
Confusing if-else with loops
Thinking if-else declares variables
Mixing if-else with function definitions
2. Which of the following is the correct syntax for an if-else statement in C?
easy
A. if (condition) then { /* code */ } else { /* code */ }
B. if condition then { /* code */ } else { /* code */ }
C. if (condition) { /* code */ } else { /* code */ }
D. if condition { /* code */ } else { /* code */ }
Solution
Step 1: Recall C syntax rules for if-else
In C, conditions must be inside parentheses and braces {} are used for code blocks.
Step 2: Check each option
Only if (condition) { /* code */ } else { /* code */ } uses parentheses around the condition and braces correctly without extra keywords like 'then'.
Final Answer:
if (condition) { /* code */ } else { /* code */ } -> Option C
Quick Check:
Correct syntax uses parentheses and braces [OK]
Hint: Remember: if(condition) with braces {} [OK]
Common Mistakes:
Omitting parentheses around condition
Using 'then' keyword (not in C)
Skipping braces for multiple statements
3. What will be the output of this C code?
#include
int main() {
int x = 10;
if (x > 5) {
printf("Greater\n");
} else {
printf("Smaller\n");
}
return 0;
}
medium
A. Greater
B. Smaller
C. 10
D. No output
Solution
Step 1: Evaluate the condition x > 5
Variable x is 10, which is greater than 5, so the condition is true.
Step 2: Determine which block runs
Since the condition is true, the code inside the if block runs, printing "Greater".
Final Answer:
Greater -> Option A
Quick Check:
10 > 5 is true, so prints "Greater" [OK]
Hint: Check if condition is true or false to pick output [OK]
Common Mistakes:
Confusing which block runs on true condition
Ignoring the newline character in printf
Assuming else block runs when condition is true
4. Find the error in this if-else code snippet:
int a = 3;
if a > 0
printf("Positive\n");
else
printf("Non-positive\n");
medium
A. Missing semicolon after if statement
B. Missing parentheses around condition in if statement
C. Missing braces around printf statements
D. Incorrect else keyword
Solution
Step 1: Check syntax of if condition
In C, the condition in an if statement must be inside parentheses (). Here, it is missing.
Step 2: Verify other parts
Semicolons after printf are present, braces are optional for single statements, and else keyword is correct.
Final Answer:
Missing parentheses around condition in if statement -> Option B
Quick Check:
if condition needs parentheses ( ) [OK]
Hint: Always put condition inside parentheses ( ) [OK]
Common Mistakes:
Forgetting parentheses in if condition
Thinking braces are always required for single statements
Misplacing else keyword
5. You want to write a program that prints "Even" if a number is even, and "Odd" if it is odd. Which if-else code correctly does this in C?
hard
A. if (num % 2 == 0) { printf("Even\n"); } else { printf("Odd\n"); }
B. if (num / 2 == 0) { printf("Even\n"); } else { printf("Odd\n"); }
C. if (num % 2 = 0) { printf("Even\n"); } else { printf("Odd\n"); }
D. if (num % 2 != 0) { printf("Even\n"); } else { printf("Odd\n"); }
Solution
Step 1: Understand how to check even numbers
A number is even if dividing by 2 leaves remainder 0, which is checked by num % 2 == 0.
Step 2: Analyze each option
if (num % 2 == 0) { printf("Even\n"); } else { printf("Odd\n"); } correctly uses modulus operator and equality check. if (num / 2 == 0) { printf("Even\n"); } else { printf("Odd\n"); } uses division instead of modulus. if (num % 2 = 0) { printf("Even\n"); } else { printf("Odd\n"); } uses assignment (=) instead of comparison (==). if (num % 2 != 0) { printf("Even\n"); } else { printf("Odd\n"); } reverses the logic.
Final Answer:
if (num % 2 == 0) { printf("Even\n"); } else { printf("Odd\n"); } -> Option A
Quick Check:
Use modulus == 0 to check even [OK]
Hint: Use num % 2 == 0 to test even numbers [OK]
Common Mistakes:
Using division instead of modulus
Using = instead of == in condition
Reversing even and odd logic
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