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Cprogramming~15 mins

If statement in C - Mini Project: Build & Apply

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If Statement Basics in C
📖 Scenario: You are creating a simple program to check if a person is old enough to vote. Voting age is 18 years or older.
🎯 Goal: Build a C program that uses an if statement to check a person's age and print whether they can vote or not.
📋 What You'll Learn
Create an integer variable called age with the value 20
Create an integer variable called voting_age with the value 18
Use an if statement to check if age is greater than or equal to voting_age
Print "You can vote!" if the condition is true
Print "You cannot vote yet." if the condition is false
💡 Why This Matters
🌍 Real World
Checking age eligibility is common in many real-world applications like voting, driving, or buying age-restricted products.
💼 Career
Understanding if statements is fundamental for any programming job because it helps make decisions in code.
Progress0 / 4 steps
1
Create the age variable
Create an integer variable called age and set it to 20.
C
Hint

Use int age = 20; inside the main function.

2
Create the voting age variable
Create an integer variable called voting_age and set it to 18.
C
Hint

Use int voting_age = 18; inside the main function after age.

3
Write the if statement to check voting eligibility
Use an if statement to check if age is greater than or equal to voting_age. Inside the if block, write printf("You can vote!\n");. Use an else block to print "You cannot vote yet.\n".
C
Hint

Use if (age >= voting_age) and else with printf statements inside each block.

4
Print the result
Run the program and print the output. Use printf statements inside the if and else blocks as before. The program should print You can vote!.
C
Hint

Compile and run the program to see the output.

Practice

(1/5)
1. What does an if statement do in C programming?
easy
A. It stores data in memory.
B. It repeats code multiple times.
C. It runs code only if a condition is true.
D. It defines a new function.

Solution

  1. Step 1: Understand the purpose of an if statement

    An if statement checks a condition and decides whether to run the code inside it.
  2. Step 2: Compare options with the if statement behavior

    Only It runs code only if a condition is true. correctly describes that the code runs only if the condition is true.
  3. Final Answer:

    It runs code only if a condition is true. -> Option C
  4. Quick Check:

    If statement = runs code if true [OK]
Hint: If condition true, run code inside braces [OK]
Common Mistakes:
  • Confusing if with loops
  • Thinking if stores data
  • Mixing if with function definition
2. Which of the following is the correct syntax for an if statement in C?
easy
A. if (condition) { printf("Hello"); }
B. if (condition) printf("Hello")
C. if condition: printf("Hello");
D. if condition { printf("Hello"); }

Solution

  1. Step 1: Recall correct if statement syntax in C

    The condition must be inside parentheses, and the code block inside braces.
  2. Step 2: Check each option

    if (condition) { printf("Hello"); } uses parentheses for condition and braces for code block, which is correct syntax.
  3. Final Answer:

    if (condition) { printf("Hello"); } -> Option A
  4. Quick Check:

    Parentheses + braces = correct if syntax [OK]
Hint: Use parentheses for condition and braces for code block [OK]
Common Mistakes:
  • Omitting parentheses around condition
  • Using colon instead of braces
  • Missing semicolon after printf
3. What will be the output of this code?
int x = 5;
if (x > 3) {
    printf("Yes");
} else {
    printf("No");
}
medium
A. Yes
B. No
C. Error
D. No output

Solution

  1. Step 1: Evaluate the condition x > 3

    Since x is 5, 5 > 3 is true.
  2. Step 2: Determine which block runs

    The if block runs and prints "Yes" because the condition is true.
  3. Final Answer:

    Yes -> Option A
  4. Quick Check:

    5 > 3 is true, prints Yes [OK]
Hint: If condition true, prints inside if block [OK]
Common Mistakes:
  • Confusing else block execution
  • Assuming syntax error without checking code
  • Ignoring condition evaluation
4. Find the error in this code snippet:
int a = 10;
if a > 5 {
    printf("Big");
}
medium
A. Variable a is not declared
B. Missing semicolon after printf
C. Braces should be parentheses
D. Condition must be inside parentheses

Solution

  1. Step 1: Check if statement syntax

    The condition in an if statement must be inside parentheses in C.
  2. Step 2: Identify the error in the code

    The code has if a > 5 { ... } without parentheses around a > 5, which is incorrect.
  3. Final Answer:

    Condition must be inside parentheses -> Option D
  4. Quick Check:

    Condition needs parentheses [OK]
Hint: Always put condition inside parentheses [OK]
Common Mistakes:
  • Using braces instead of parentheses for condition
  • Forgetting semicolon after statements
  • Assuming variable not declared
5. Consider this code:
int n = 0;
if (n) {
    printf("True");
} else {
    printf("False");
}

What will be printed and why?
hard
A. True, because n is zero
B. False, because zero is false in C
C. Error, n must be boolean
D. No output, program crashes

Solution

  1. Step 1: Understand how C treats integers in conditions

    In C, zero means false, any nonzero means true.
  2. Step 2: Evaluate the condition if (n)

    Since n is 0, the condition is false, so else block runs.
  3. Step 3: Determine output

    The else block prints "False".
  4. Final Answer:

    False, because zero is false in C -> Option B
  5. Quick Check:

    Zero = false, prints False [OK]
Hint: Zero means false, nonzero means true in if conditions [OK]
Common Mistakes:
  • Thinking zero is true
  • Expecting boolean type only
  • Assuming program error
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10 questions~5 mineasy hard