[Solved] How can you modify this loop to skip printing the number 4?for(int i = 1; i — Ans: Add 'if(i == 4) continue;' inside the loop before printf | C

C - Loops

How can you modify this loop to skip printing the number 4?

for(int i = 1; i <= 5; i++) {
    printf("%d ", i);
}

AAdd 'if(i == 4) continue;' inside the loop before printf

BChange loop to 'for(int i = 1; i < 4; i++)' only

CUse 'break' when i equals 4

DRemove the printf statement

Step-by-Step Solution

Solution:

Step 1: Understand the goal to skip printing 4
We want to print 1, 2, 3, 5 but skip 4.
Step 2: Use continue to skip printing 4
Adding 'if(i == 4) continue;' skips the rest of the loop body for i=4, so printf is not called.
Final Answer:
Add 'if(i == 4) continue;' inside the loop before printf -> Option A
Quick Check:
Continue skips current iteration [OK]

Quick Trick: Use continue to skip unwanted iterations [OK]

Common Mistakes:

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How can you modify this loop to skip printing the number 4?