[Solved] Identify the error in this for loop:for(int i = 0; i — Ans: Missing semicolon after printf statement | C

C - Loops

Identify the error in this for loop:

for(int i = 0; i < 5; i++)
    printf("%d ", i)

AIncorrect loop condition syntax

BMissing semicolon after printf statement

CLoop variable not declared

DMissing braces around loop body

Step-by-Step Solution

Solution:

Step 1: Check syntax of loop and statements
The loop syntax is correct, but the printf statement lacks a semicolon at the end.
Step 2: Identify the missing semicolon
In C, each statement must end with a semicolon; missing it causes a syntax error.
Final Answer:
Missing semicolon after printf statement -> Option B
Quick Check:
Missing semicolon causes syntax error [OK]

Quick Trick: Every statement needs a semicolon [OK]

Common Mistakes:

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