[Solved] Why does a for loop sometimes run one less time than expected when using i as the condition? — Ans: Because the loop stops before i equals n, excluding n | C

C - Loops

Why does a for loop sometimes run one less time than expected when using i < n as the condition?

ABecause the initialization is incorrect

BBecause the loop increments i twice each iteration

CBecause the loop stops before i equals n, excluding n

DBecause the loop body is empty

Step-by-Step Solution

Solution:

Step 1: Understand the loop condition i < n
The loop runs while i is less than n, so it stops once i reaches n.
Step 2: Explain why loop excludes n
Since i must be less than n, the loop never runs when i equals n, causing one less iteration than if condition was i <= n.
Final Answer:
Because the loop stops before i equals n, excluding n -> Option C
Quick Check:
i < n excludes n, so loop runs one less time [OK]

Quick Trick: i < n excludes n, causing one less iteration [OK]

Common Mistakes:

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Why does a for loop sometimes run one less time than expected when using i as the condition?