Else–if ladder in C - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to check if a number is positive.

C

if (num [1] 0) {
    printf("Positive\n");
}

Drag options to blanks, or click blank then click option'

A<

B!=

C==

D>

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' will check for negative numbers.

Using '==' checks only if number equals zero.

The condition num > 0 checks if the number is positive.

2fill in blank

medium

Complete the else-if ladder to check if a number is zero.

C

if (num > 0) {
    printf("Positive\n");
} else if (num [1] 0) {
    printf("Zero\n");
}

Drag options to blanks, or click blank then click option'

A==

B<

C!=

D>

Attempts:

3 left

💡 Hint

Common Mistakes

Using '=' instead of '==' causes assignment, not comparison.

Using '!=' checks for not equal, which is incorrect here.

The condition num == 0 checks if the number is exactly zero.

3fill in blank

hard

Fix the error in the else-if ladder condition to check if a number is negative.

C

if (num > 0) {
    printf("Positive\n");
} else if (num [1] 0) {
    printf("Negative\n");
}

Drag options to blanks, or click blank then click option'

A>

B!=

C<

D==

Attempts:

3 left

💡 Hint

Common Mistakes

Using '>' checks for positive numbers, not negative.

Using '==' checks for zero, not negative numbers.

The condition num < 0 correctly checks if the number is negative.

4fill in blank

hard

Fill both blanks to complete the else-if ladder that prints the sign of a number.

C

if (num [1] 0) {
    printf("Positive\n");
} else if (num [2] 0) {
    printf("Negative\n");
} else {
    printf("Zero\n");
}

Drag options to blanks, or click blank then click option'

A>

B<

C==

D!=

Attempts:

3 left

💡 Hint

Common Mistakes

Swapping the operators will give wrong results.

Using '==' in these conditions is incorrect.

The first condition checks if num > 0 (positive), the second if num < 0 (negative), else zero.

5fill in blank

hard

Fill all three blanks to complete the else-if ladder that categorizes a number.

C

if (num [1] 0) {
    printf("Positive\n");
} else if (num [2] 0) {
    printf("Negative\n");
} else if (num [3] 0) {
    printf("Zero\n");
}

Drag options to blanks, or click blank then click option'

A>

B<

C==

D!=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '!=' instead of '==' for zero check.

Mixing up the order of conditions.

The conditions check if num > 0 (positive), num < 0 (negative), and num == 0 (zero).

Practice

1. What does an else-if ladder do in C programming?

easy

A. Checks multiple conditions one by one and executes the first true block

B. Runs all conditions regardless of their truth value

C. Only executes the last condition in the ladder

D. Skips all conditions and runs the else block always

Solution

1. Step 1: Understand the purpose of else-if ladder

   An else-if ladder is used to check multiple conditions sequentially.

2. Step 2: Identify how conditions are executed

   Only the first condition that is true will have its block executed, and the rest are skipped.

3. Final Answer:

   Checks multiple conditions one by one and executes the first true block -> Option A

4. Quick Check:

   Else-if ladder = first true condition runs [OK]

Hint: Remember: else-if stops at first true condition [OK]

Common Mistakes:

• Thinking all conditions run regardless
• Believing else runs always
• Confusing else-if with multiple ifs

2. Which of the following is the correct syntax for an else-if ladder in C?

easy

A. if(condition) { } else(condition) { } else if { }

B. if(condition) { } else if(condition) { } else { }

C. if(condition) { } else if { } else(condition) { }

D. if(condition) { } else if(condition) { } else if

Solution

1. Step 1: Review correct else-if syntax

   The else-if ladder uses: if(condition) { } else if(condition) { } else { }.

2. Step 2: Check each option for syntax errors

   if(condition) { } else if(condition) { } else { } matches correct syntax; others have misplaced else or missing conditions.

3. Final Answer:

   if(condition) { } else if(condition) { } else { } -> Option B

4. Quick Check:

   Correct else-if syntax = if(condition) { } else if(condition) { } else { } [OK]

Hint: else if always needs a condition in parentheses [OK]

Common Mistakes:

• Writing else with a condition
• Omitting parentheses in else-if
• Ending else-if without braces

3. What will be the output of the following C code?

int x = 15;
if (x < 10) {
  printf("Less than 10\n");
} else if (x < 20) {
  printf("Less than 20\n");
} else {
  printf("20 or more\n");
}

medium

A. Less than 20

B. 20 or more

C. Less than 10

D. No output

Solution

1. Step 1: Evaluate first condition (x < 10)

   x is 15, which is not less than 10, so this block is skipped.

2. Step 2: Evaluate second condition (x < 20)

   15 is less than 20, so this block runs and prints "Less than 20".

3. Final Answer:

   Less than 20 -> Option A

4. Quick Check:

   15 < 20 = true, prints "Less than 20" [OK]

Hint: Check conditions top to bottom, first true runs [OK]

Common Mistakes:

• Choosing first condition without checking value
• Assuming else always runs
• Confusing output strings

4. Find the error in this else-if ladder code snippet:

int num = 5;
if (num > 10)
  printf("Greater than 10\n");
else if num > 0
  printf("Positive number\n");
else
  printf("Zero or negative\n");

medium

A. Missing semicolon after printf statements

B. else cannot be used without if

C. Incorrect variable name used

D. Missing parentheses around condition in else-if

Solution

1. Step 1: Check syntax of else-if condition

   In C, else-if condition must be inside parentheses: else if (condition).

2. Step 2: Identify the error in given code

   Code has else if num > 0 without parentheses, causing syntax error.

3. Final Answer:

   Missing parentheses around condition in else-if -> Option D

4. Quick Check:

   else-if needs parentheses [OK]

Hint: Always put conditions in parentheses after else if [OK]

Common Mistakes:

• Forgetting parentheses in else-if
• Missing semicolons after printf
• Misusing else without if

5. You want to write a program that prints "Child" if age < 13, "Teen" if age is between 13 and 19 inclusive, "Adult" if age is between 20 and 59 inclusive, and "Senior" if age is 60 or more. Which else-if ladder correctly implements this?

hard

A. if (age < 13) { printf("Child\n"); } else if (age < 20) { printf("Teen\n"); } else if (age < 59) { printf("Adult\n"); } else { printf("Senior\n"); }

B. if (age <= 13) { printf("Child\n"); } else if (age < 19) { printf("Teen\n"); } else if (age < 59) { printf("Adult\n"); } else { printf("Senior\n"); }

C. if (age <= 12) { printf("Child\n"); } else if (age <= 19) { printf("Teen\n"); } else if (age <= 59) { printf("Adult\n"); } else { printf("Senior\n"); }

D. if (age < 13) { printf("Child\n"); } else if (age < 19) { printf("Teen\n"); } else if (age <= 59) { printf("Adult\n"); } else { printf("Senior\n"); }

Solution

1. Step 1: Analyze age ranges for each category

   Child: age < 13 means age ≤ 12; Teen: 13 to 19 inclusive; Adult: 20 to 59 inclusive; Senior: 60 or more.

2. Step 2: Check each option's conditions

   if (age <= 12) { printf("Child\n"); } else if (age <= 19) { printf("Teen\n"); } else if (age <= 59) { printf("Adult\n"); } else { printf("Senior\n"); } correctly uses age ≤ 12 for Child, ≤ 19 for Teen, ≤ 59 for Adult, else Senior.

3. Final Answer:

   if (age <= 12) { printf("Child\n"); } else if (age <= 19) { printf("Teen\n"); } else if (age <= 59) { printf("Adult\n"); } else { printf("Senior\n"); } -> Option C

4. Quick Check:

   Correct age ranges with inclusive bounds = if (age <= 12) { printf("Child\n"); } else if (age <= 19) { printf("Teen\n"); } else if (age <= 59) { printf("Adult\n"); } else { printf("Senior\n"); } [OK]

Hint: Use inclusive bounds carefully in else-if conditions [OK]

Common Mistakes:

• Using wrong comparison operators
• Overlapping or missing age ranges
• Incorrect boundary values