[Solved] Identify the error in this else-if ladder code snippet:int x = 5; if (x > 10) printf("Greater than 10\n"); else if x > 5 { printf("Greater than 5\n"); } else { printf("5 or less\n"); } | C

C - onditional Statements

Identify the error in this else-if ladder code snippet:

int x = 5;
if (x > 10)
  printf("Greater than 10\n");
else if x > 5 {
  printf("Greater than 5\n");
} else {
  printf("5 or less\n");
}

AMissing parentheses around condition in else if

BMissing semicolon after printf

CIncorrect use of braces in else block

DVariable x not declared

Step-by-Step Solution

Solution:

Step 1: Check else-if syntax
The else-if condition must be inside parentheses. Here, 'else if x > 5' misses parentheses.
Step 2: Verify other parts
Semicolons are present after each printf. Braces and variable declaration are correct.
Final Answer:
Missing parentheses around condition in else if -> Option A
Quick Check:
Else-if condition needs parentheses [OK]

Quick Trick: Always put conditions in parentheses in else-if [OK]

Common Mistakes:

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