[Solved] Why is it important to use the address-of operator (&) with variables in scanf? — Ans: Because scanf needs the memory location to store input | C

C - Input and Output

Why is it important to use the address-of operator (&) with variables in scanf?

ABecause & converts variable to string

BBecause scanf needs the memory location to store input

CBecause & prints the variable value

DBecause & is optional and used for style

Step-by-Step Solution

Solution:

Step 1: Understand how scanf stores input
scanf stores input directly into the variable's memory location.
Step 2: Role of & operator
The & operator gives the memory address of the variable so scanf can write the input there.
Final Answer:
Because scanf needs the memory location to store input -> Option B
Quick Check:
Use & to give scanf variable address [OK]

Quick Trick: Use & to give scanf variable's memory address [OK]

Common Mistakes:

Master "Input and Output" in C

9 interactive learning modes - each teaches the same concept differently

More C Quizzes

Why is it important to use the address-of operator (&) with variables in scanf?