[Solved] Find the error in this C code snippet that reads and prints a number: #include <stdio.h> int main() { int num; printf("Enter number: "); scanf("%d", num); printf("Number is %d\n", num); return 0; } | C

C - Input and Output

Find the error in this C code snippet that reads and prints a number:

#include <stdio.h>
int main() {
  int num;
  printf("Enter number: ");
  scanf("%d", num);
  printf("Number is %d\n", num);
  return 0;
}

AMissing & before num in scanf

BWrong format specifier in printf

CMissing semicolon after printf

DNo error

Step-by-Step Solution

Solution:

Step 1: Check scanf argument
scanf needs the address of variable to store input, so &num is required.
Step 2: Verify other parts
printf uses correct format %d and semicolons are present.
Final Answer:
Missing & before num in scanf -> Option A
Quick Check:
Use & with scanf variable [OK]

Quick Trick: Always use & before variable in scanf [OK]

Common Mistakes:

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