Break statement in C - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to exit the loop when i equals 5.

C

for(int i = 0; i < 10; i++) {
    if(i == 5) {
        [1];
    }
    printf("%d\n", i);
}

Drag options to blanks, or click blank then click option'

Acontinue

Breturn

Cexit

Dbreak

Attempts:

3 left

💡 Hint

Common Mistakes

Using continue instead of break, which skips the rest of the loop iteration but does not exit the loop.

Using return or exit which exit the function or program instead of just the loop.

The break statement immediately exits the nearest enclosing loop.

2fill in blank

medium

Complete the code to stop the while loop when count reaches 3.

C

int count = 0;
while(1) {
    if(count == 3) {
        [1];
    }
    printf("Count: %d\n", count);
    count++;
}

Drag options to blanks, or click blank then click option'

Acontinue

Bexit

Cbreak

Dreturn

Attempts:

3 left

💡 Hint

Common Mistakes

Using continue which skips the current iteration but does not exit the loop.

Using exit or return which exit the program or function.

break exits the loop when count equals 3.

3fill in blank

hard

Fix the error in the code to exit the for loop when num is 7.

C

for(int num = 0; num < 10; num++) {
    if(num == 7) {
        [1];
    }
    printf("%d\n", num);
}

Drag options to blanks, or click blank then click option'

Acontinue

Bbreak

Cexit()

Dreturn

Attempts:

3 left

💡 Hint

Common Mistakes

Using continue which does not exit the loop.

Using exit() or return which exit the program or function.

break exits the loop correctly; exit() and return affect the program or function, not just the loop.

4fill in blank

hard

Fill both blanks to create a loop that prints numbers until it reaches 4, then stops.

C

for(int i = 0; i < 10; i++) {
    if(i [1] 4) {
        [2];
    }
    printf("%d\n", i);
}

Drag options to blanks, or click blank then click option'

A==

B<

Cbreak

Dcontinue

Attempts:

3 left

💡 Hint

Common Mistakes

Using < instead of == in the condition.

Using continue instead of break to exit the loop.

The condition i == 4 triggers break to exit the loop.

5fill in blank

hard

Fill all three blanks to create a loop that stops printing when the character 'q' is found in the array.

C

char letters[] = {'a', 'b', 'c', 'q', 'd'};
for(int [1] = 0; [2] < 5; [3]++) {
    if(letters[i] == 'q') {
        break;
    }
    printf("%c\n", letters[i]);
}

Drag options to blanks, or click blank then click option'

Ai

Dj

Attempts:

3 left

💡 Hint

Common Mistakes

Using different variable names in the loop declaration.

Using a variable not declared or inconsistent.

The loop variable i is used consistently in initialization, condition, and increment.