You want a bash function swap that prints its two arguments in reverse order. Which function definition achieves this?

hard🚀 Application Q8 of 15

Bash Scripting - Functions

You want a bash function swap that prints its two arguments in reverse order. Which function definition achieves this?

Aswap() { echo "$2 $1"; }

Bswap() { echo "$1 $2"; }

Cswap() { echo "$3 $4"; }

Dswap() { echo "$0 $1"; }

Step-by-Step Solution

Solution:

Step 1: Understand the goal
The function should print the second argument first, then the first argument.
Step 2: Match the correct argument order
Using $2 $1 prints arguments in reverse order. Other options print original order or wrong variables.
Final Answer:
swap() { echo "$2 $1"; } -> Option A
Quick Check:
Reverse order = echo $2 $1 [OK]

Quick Trick: Swap arguments by echoing $2 then $1 [OK]

Common Mistakes:

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