$1 and $2 represent inside a bash function?$1 and $2 are the first and second arguments passed to the function when it is called.
You use $3 to access the third argument passed to the function.
$1 inside a bash function refers to the first argument passed to the script, not the function.False. Inside a function, $1 refers to the first argument passed to that function, not the script.
You call the function followed by the arguments separated by spaces, like myfunc arg1 arg2. Inside the function, $1 will be arg1, $2 will be arg2.
$1 inside it?$1 will be empty or unset because no argument was passed to the function.
$2 represent?$2 inside a function is the second argument passed to that function.
greet?In bash, you call functions with arguments separated by spaces, like greet arg1 arg2.
$1 be inside a function if you call it without any arguments?If no arguments are passed, $1 inside the function is empty or unset.
$1 is the correct way to access the first argument inside a bash function.
func apple banana, what is $2 inside func?$2 is the second argument passed, which is banana.
$1 and $2 inside a bash function with an example.$1 inside a bash function but you did not pass any arguments when calling it?