[Solved] What does the bash expression ${var/old/new} do? - Ans: Replaces the first occurrence of 'old' with 'new' in the variable 'var' | Bash Scripting

Bash Scripting - String Operations

What does the bash expression ${var/old/new} do?

AReplaces the first occurrence of 'old' with 'new' in the variable 'var'

BReplaces all occurrences of 'old' with 'new' in the variable 'var'

CDeletes the variable 'var' if it contains 'old'

DPrints the variable 'var' without any changes

Step-by-Step Solution

Solution:

Step 1: Understand the syntax ${var/old/new}
This syntax replaces only the first occurrence of 'old' with 'new' in the string stored in 'var'.
Step 2: Differentiate from global replacement
Using double slashes like ${var//old/new} replaces all occurrences, but single slash replaces only the first.
Final Answer:
Replaces the first occurrence of 'old' with 'new' in the variable 'var' -> Option A
Quick Check:
String replacement first occurrence = C [OK]

Quick Trick: Single slash replaces first occurrence only [OK]

Common Mistakes:

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What does the bash expression ${var/old/new} do?