[Solved] What is the output of this Bash script? items=("pen" "pencil" "eraser") items+=("marker") unset 'items[1]' for item in "${items[@]}"; do echo "$item" done | Bash Scripting

Bash Scripting - Arrays

What is the output of this Bash script?

items=("pen" "pencil" "eraser")
items+=("marker")
unset 'items[1]'
for item in "${items[@]}"; do
  echo "$item"
done

Apen marker

Bpen pencil eraser marker

Cpen eraser marker

Dpen pencil marker

Step-by-Step Solution

Solution:

Step 1: Analyze array modifications
Initial array: ["pen", "pencil", "eraser"]. Then add "marker" at the end: ["pen", "pencil", "eraser", "marker"]. Then remove element at index 1 ("pencil").
Step 2: Determine final array elements
After removal, array elements are: index 0="pen", index 2="eraser", index 3="marker". Looping over ${items[@]} skips unset indices, so output is "pen", "eraser", "marker" each on a new line.
Final Answer:
pen eraser marker -> Option C
Quick Check:
Remove index 1 and add marker = pen, eraser, marker [OK]

Quick Trick: Unset removes element but keeps others; loop skips unset [OK]

Common Mistakes:

MISTAKES

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