Bash Scripting - Functions
What will be the output of this script?
print_args() {
echo "$2 $1"
}
print_args one twoprint_args() {
echo "$2 $1"
}
print_args one twoone as $1 and two as $2.$2 first, then $1, so output is "two one".15+ quiz questions · All difficulty levels · Free
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