Bash Scripting - Functions
What will the following bash function print when called as
show_args apple banana?show_args() {
echo "$1 and $2 are fruits"
}What will the following bash function print when called as show_args apple banana?
easy🧠 Conceptual Q2 of 15
Step-by-Step Solution
Solution:
Step 1: Identify the arguments passed to the function
The function is called with two arguments:appleandbanana. So,$1= apple,$2= banana.Step 2: Understand the echo statement
The echo prints the values of$1and$2followed by the text "are fruits".Final Answer:
apple and banana are fruits -> Option DQuick Check:
Arguments $1 and $2 print in order [OK]
Quick Trick: Arguments print in order: $1 first, $2 second [OK]
Common Mistakes:
MISTAKES- Swapping $1 and $2 values
- Printing variable names instead of values
- Ignoring the order of arguments
Master "Functions" in Bash Scripting
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