[Solved] Find the error in this bash code: declare -i val=8 val=val*2 echo $val - Ans: val=val*2 is treated as string, not arithmetic | Bash Scripting

Bash Scripting - Variables

Find the error in this bash code:

declare -i val=8
val=val*2
echo $val

AMissing quotes around val*2

Bdeclare -i cannot be used with val

Cval=val*2 is treated as string, not arithmetic

DSyntax error in echo statement

Step-by-Step Solution

Solution:

Step 1: Analyze assignment
Expression val=val*2 assigns string "val*2" to val, not arithmetic.
Step 2: Correct arithmetic syntax
Use val=$((val * 2)) to multiply correctly.
Final Answer:
val=val*2 is treated as string, not arithmetic -> Option C
Quick Check:
Arithmetic requires $(( )) in bash [OK]

Quick Trick: Use $(( )) for math, else it's string assignment [OK]

Common Mistakes:

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