[Solved] Why does this script fail?for i in {1..5}; do echo i; done - Ans: Variable i is not expanded with $ | Bash Scripting

Bash Scripting - Loops

Why does this script fail?

for i in {1..5}; do echo i; done

AVariable i is not expanded with $

BBrace expansion is incorrect

CMissing 'done' keyword

DSyntax error in for loop

Step-by-Step Solution

Solution:

Step 1: Check variable usage in echo
Echo prints the literal string 'i' because $ is missing before i.
Step 2: Confirm brace expansion and loop syntax
Brace expansion and loop syntax are correct, so error is variable expansion.
Final Answer:
Variable i is not expanded with $ -> Option A
Quick Check:
Use $ to expand variables in echo = Variable i is not expanded with $ [OK]

Quick Trick: Always use $ before variable names to print their values [OK]

Common Mistakes:

MISTAKES

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Why does this script fail?