Integer variables in Bash Scripting - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to declare an integer variable named num with value 10.

Bash Scripting

declare -i [1]=10

Drag options to blanks, or click blank then click option'

Anum

Bnumber

Cint

Dvalue

Attempts:

3 left

💡 Hint

Common Mistakes

Using a variable name different from 'num'.

Forgetting to declare the variable as integer.

The declare -i command declares an integer variable. Here, num is the variable name.

2fill in blank

medium

Complete the code to add 5 to the integer variable count.

Bash Scripting

count=[1]+5

Drag options to blanks, or click blank then click option'

Acount

B$count

C"count"

D'count'

Attempts:

3 left

💡 Hint

Common Mistakes

Using the variable name without $.

Using quotes around the variable name.

To use the current value of count, prefix it with $ to get its value.

3fill in blank

hard

Fix the error in the code to correctly increment the integer variable score by 1.

Bash Scripting

(( [1]++ ))

Drag options to blanks, or click blank then click option'

A'score'

B$score

C"score"

Dscore

Attempts:

3 left

💡 Hint

Common Mistakes

Using $score inside arithmetic expression.

Using quotes around the variable name.

Inside arithmetic expressions, use the variable name without $ or quotes.

4fill in blank

hard

Fill in the blanks to declare an integer variable total and assign it the sum of a and b.

Bash Scripting

declare -i [1]=[2]+[3]

Drag options to blanks, or click blank then click option'

Atotal

Ba

Cb

Dsum

Attempts:

3 left

💡 Hint

Common Mistakes

Using the wrong variable name for declaration.

Using the same variable twice instead of both a and b.

Declare total as integer and assign it the sum of a and b. Both a and b are variables used in the expression.

5fill in blank

hard

Fill all three blanks to create a loop that counts from 1 to 5 and prints each number.

Bash Scripting

for [1] in [2]; do
  echo [3]
done

Drag options to blanks, or click blank then click option'

Ai

B1 2 3 4 5

C$i

Dseq 1 5

Attempts:

3 left

💡 Hint

Common Mistakes

Using the variable name without $ in echo.

Using seq 1 5 without command substitution.

Using quotes around the list of numbers.

Use i as the loop variable, iterate over the list 1 2 3 4 5, and print the value of i with $i.