How can you calculate the average of three integer variables x, y, and z using arithmetic expansion in bash?

hard🚀 Application Q9 of 15

Bash Scripting - Quoting and Expansion

How can you calculate the average of three integer variables x, y, and z using arithmetic expansion in bash?

Aavg=$((x + y + z / 3))

Bavg=$(((x + y + z) / 3))

Cavg=$((x + y + z) / 3.0)

Davg=$((x + y + z) // 3)

Step-by-Step Solution

Solution:

Step 1: Understand integer division in bash
Bash arithmetic expansion supports integer math only.
Step 2: Evaluate each option
avg=$(((x + y + z) / 3)) correctly sums all variables then divides by 3. avg=$((x + y + z / 3)) divides z by 3 first due to operator precedence. avg=$((x + y + z) / 3.0) uses floating point which is unsupported. avg=$((x + y + z) // 3) uses // which is invalid in bash.
Final Answer:
avg=$(((x + y + z) / 3)) -> Option B
Quick Check:
Correct average calculation = avg=$(((x + y + z) / 3)) [OK]

Quick Trick: Use parentheses to control order in $(( )) [OK]

Common Mistakes:

MISTAKES

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