How can you use break and continue together to print numbers 1 to 10 but stop the loop if number is greater than 7 and skip printing 5?
hard🚀 Application Q9 of 15
Bash Scripting - Loops
How can you use break and continue together to print numbers 1 to 10 but stop the loop if number is greater than 7 and skip printing 5?
Afor i in {1..10}; do if (( i > 7 )); then break; elif (( i == 5 )); then continue; fi; echo $i; done
Bfor i in {1..10}; do if (( i == 5 )); then break; elif (( i > 7 )); then continue; fi; echo $i; done
Cfor i in {1..10}; do if (( i > 7 )); then continue; elif (( i == 5 )); then break; fi; echo $i; done
Dfor i in {1..10}; do if (( i == 5 )); then continue; elif (( i == 7 )); then break; fi; echo $i; done
Step-by-Step Solution
Solution:
Step 1: Understand conditions for break and continue
Break stops loop if number > 7. Continue skips printing 5.
Step 2: Check option logic
for i in {1..10}; do if (( i > 7 )); then break; elif (( i == 5 )); then continue; fi; echo $i; done correctly breaks if >7 and continues if ==5 before printing. Others swap or misuse break and continue.
Final Answer:
for i in {1..10}; do if (( i > 7 )); then break; elif (( i == 5 )); then continue; fi; echo $i; done -> Option A
Quick Check:
Break >7, continue 5 skip = A [OK]
Quick Trick:Use break for stop, continue for skip in same loop [OK]
Common Mistakes:
MISTAKES
Swapping break and continue conditions
Not using elif causing both to trigger
Incorrect order of conditions
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