if-then-else in Bash Scripting - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to check if the variable num is equal to 10.

Bash Scripting

if [ "$num" [1] 10 ]; then
  echo "Number is ten"
fi

Drag options to blanks, or click blank then click option'

A==

B=

C!=

D-eq

Attempts:

3 left

💡 Hint

Common Mistakes

Using '=' or '==' which are for strings, not integers.

Forgetting spaces around brackets.

In bash, to compare integers inside [ ], use -eq for equality.

2fill in blank

medium

Complete the code to print "Positive" if the variable num is greater than zero.

Bash Scripting

if [ "$num" [1] 0 ]; then
  echo "Positive"
fi

Drag options to blanks, or click blank then click option'

A-gt

B-lt

C-eq

D-ne

Attempts:

3 left

💡 Hint

Common Mistakes

Using string comparison operators instead of numeric ones.

Using -lt which means less than.

Use -gt to check if a number is greater than another in bash.

3fill in blank

hard

Fix the error in the if statement to correctly check if word equals "hello".

Bash Scripting

if [[ $word [1] "hello" ]]; then
  echo "Greeting detected"
fi

Drag options to blanks, or click blank then click option'

A-eq

B=

C==

D!=

Attempts:

3 left

💡 Hint

Common Mistakes

Using single equals = inside [[ ]] which is less common and can cause issues.

Using numeric operators like -eq for strings.

Inside double brackets [[ ]], use == for string comparison.

4fill in blank

hard

Fill both blanks to complete the if-else statement that prints "Even" if num is divisible by 2, else prints "Odd".

Bash Scripting

if [ $((num [1] 2)) [2] 0 ]; then
  echo "Even"
else
  echo "Odd"
fi

Drag options to blanks, or click blank then click option'

A%

B-eq

C-ne

D/

Attempts:

3 left

💡 Hint

Common Mistakes

Using division / instead of modulus %.

Using -ne instead of -eq.

Use modulus operator % to get remainder and -eq to check if it equals zero.

5fill in blank

hard

Fill all three blanks to create a nested if-else that prints "Positive", "Zero", or "Negative" based on num.

Bash Scripting

if [ $num [1] 0 ]; then
  echo "Positive"
elif [ $num [2] 0 ]; then
  echo "Zero"
else
  echo "Negative"
fi

Drag options to blanks, or click blank then click option'

A-gt

B-eq

C-lt

D-ne

Attempts:

3 left

💡 Hint

Common Mistakes

Mixing up the order of conditions.

Using string comparison operators instead of numeric ones.

Use -gt for greater than zero, -eq for zero, and -lt for less than zero.