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What is the time complexity of the binary search + preprocessing approach for the Minimum Interval to Include Each Query problem, given n intervals and m queries?

medium🪤 Complexity Trap Q13 of Q15
Intervals - Minimum Interval to Include Each Query
What is the time complexity of the binary search + preprocessing approach for the Minimum Interval to Include Each Query problem, given n intervals and m queries?
AO(n log n + m n log n)
BO(n log n + m log n * n)
CO((n + m) log n)
DO(n * m)
Step-by-Step Solution
Solution:
  1. Step 1: Analyze preprocessing

    Sorting intervals by length takes O(n log n).
  2. Step 2: Analyze per query cost

    For each query, binary search over lengths is O(log n), but coverage check scans up to O(n) intervals, so O(n log n) per query.
  3. Final Answer:

    Option A -> Option A
  4. Quick Check:

    Overall complexity is O(n log n + m n log n) due to coverage scanning [OK]
Quick Trick: Coverage check inside binary search causes O(n) scan per query [OK]
Common Mistakes:
MISTAKES
  • Assuming coverage check is O(log n) ignoring linear scan
  • Confusing n and m in complexity
  • Forgetting sorting cost
Trap Explanation:
PITFALL
  • Option B looks similar but misses the linear scan inside coverage check, making it incorrect.
Interviewer Note:
CONTEXT
  • Tests understanding of nested loops and binary search combined complexity.
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