Intervals - Meeting Rooms I
What is the time complexity of the optimal algorithm that determines if a person can attend all meetings given n intervals?
What is the time complexity of the optimal algorithm that determines if a person can attend all meetings given n intervals?
medium🪤 Complexity Trap Q5 of Q15
Step-by-Step Solution
Solution:
Step 1: Analyze sorting step
Sorting n intervals by start time takes O(n log n) time.Step 2: Analyze single pass check
Checking overlaps in one pass is O(n), dominated by sorting.Final Answer:
Option A -> Option AQuick Check:
Sorting dominates time complexity [OK]
Quick Trick: Sorting dominates complexity -> O(n log n) [OK]
Common Mistakes:
MISTAKES- Assuming O(n) without sorting
- Confusing with quadratic brute force O(n^2)
Trap Explanation:
PITFALL- Candidates often forget sorting cost and pick O(n) or O(n^2) incorrectly.
Interviewer Note:
CONTEXT- Tests understanding of time complexity in interval sorting algorithms.
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